According to Newton's Second Law of Motion :
The Force acting on an Object is equal to Product of Mass of the Object and Acceleration produced due to the Force.
Force acting = Mass of the Object × Acceleration
Given : Force = 50 newton and Mass of the Object = 10 kg
Substituting the respective values in the Formula, we get :
50 N = 10 kg × Acceleration
Acceleration of the Object = 5 m/s²
Answer:
F = 4399 KN
Explanation:
given,
mass of automobile = 890 kg
initial speed = 48 km/h
= 48 × 0.278 = 13.34 m/s
using equation of motion
v² = u² + 2 a × s
0 = 13.34² - 2 a ×0.018
a = 4943.21 m/s²
F = m × a
F = 890 × 4943.21
F = 4399456.9 N
F = 4399 KN
hence, the Net force is F = 4399 KN
Answer:
3 A
Explanation:
Answer: N = Mgcos(theta)
Therefore, the Normal reaction force is equal to Mgcos(theta)
Explanation:
See attached for a sketch.
From the attachment.
.
N = normal reaction force on block
W = weight of the block
theta = angle of the inclined plane to the horizontal
From the sketch, we can see that
N is equal in magnitude but opposite direction to Wy
N = Wy
And
Wy = Wcos(theta)
Wx = Wsin(theta)
Then,
N = Wy = Wcos(theta)
But W = mass × acceleration due to gravity = mg
N = Mgcos(theta)
Therefore, the Normal reaction force is equal to Mgcos(theta)
