Question

A 6.0-v battery maintains the electrical potential difference between two parallel metal plates separated by 1.0 mm. what is the electric field between the plates?

Answer 1

The voltage difference between the two plates can be expressed in terms of the work done on a positive test charge q when it moves from the positive to the negative plate.
E=V/d
where V is the voltage and d is the distance between the plates.
 
So,

E=6.0V/1mm= 6000 V/m. The electric field between the plates is 6000 V/m.