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Andru [333]
3 years ago
8

A 6.0-v battery maintains the electrical potential difference between two parallel metal plates separated by 1.0 mm. what is the

electric field between the plates?
Physics
1 answer:
Gnoma [55]3 years ago
5 0
The voltage<span> difference between the two plates can be expressed in terms of the </span>work<span> done on a positive test charge q when it moves from the positive to the negative plate.</span><span>
E=V/d
where V is the voltage and d is the distance between the plates.
 
So,

E=6.0V/1mm= 6000 V/m. The electric field between the plates is 6000 V/m.</span>
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Anastaziya [24]

Answer:

1.17 x 10^2 L

Explanation:

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Solving the equation for V, we find the volume

V=\frac{nRT}{p}=\frac{(4.8 mol)(0.0821 L atm/mol K)(310 K)}{1.04 atm}=117.5 L = 1.17\cdot 10^2 L

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3 years ago
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Katyanochek1 [597]

Answer:

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