Suppose the larger pump alone can empty the tank in L hours, and the smaller pump can finish the job in S hours, then each hour the large pump empties 1/L portion of the tank, and the small pump empties 1/S per hour
Working together for three hours, they empty the whole tank, which is 100% of it, so 3/L+3/S=100%=1
Larger pump can empty the tank in 4 hours less than the smaller one, so L=S-4
replace L: 3/(S-4)+3/S=1
Make the denominator the same to solve for:
3S/[S(S-4)] +3(S-4)/[S(S-4)]=1
(3S+3S-12)/[S(S-4)]=1
(3S+3S-12)=[S(S-4)]
S^2-10s+12=0
use the quadratic formula to solve for S
S is about 8.6
The answer is not whole hour.
Answer:
x(85/100)
Step-by-step explanation:
100-15 = 85
x(85/100)
Answer:
gram
Step-by-step explanation:
This is the concept of applications of polynomial equations. Given that the height of the ball is modeled by the function:
h(t)=16t^2-64t
the maximum height will be calculated as follows;
h(t)=16t(t-4)
therefore:
t=0 or t=4
h(4)=-64(4)+16(4^2)
=0
