A few applications of L'Hopital's rule gives a decent idea of how this limit will ultimately behave.
and so on. Notice that the numerator will consistently behave exponentially, while the denominator will eventually be rendered into a constant. This means the function diverges to
as
.
Hello there.
Question: <span>What is the missing number in the number sentence ?
Answer: It would be 4.
Both sides should be equal therefore the number you need is 4.
</span>Hope This Helps You!
<span>Good Luck Studying ^-^</span>
Three million, three hundred eighty eight thousand, one hundred ninety eight.
Answer:
A
Step-by-step explanation:
vertical angles congrunet (angleFJH + angle GJI)
& (angleHFJ + angle JGI congruent)
First, we have to make sure that the number of columns in the first matrix is equal to the number of rows in the second matrix.
![\left[\begin{array}{cc}1&-3&2&0\\\end{array}\right] * \left[\begin{array}{ccc}2&3&4\\1&2&3\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26-3%262%260%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%2A%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%264%5C%5C1%262%263%5Cend%7Barray%7D%5Cright%5D%20)
Since this is true, we can continue to solve the problem.
To multiply two matrices, multiply each row element in the first matrix by each column element in the second matrix. For example:
1*2 = 2
-3*1=-3
Then we add them to get our new matrix element.
-3+2=
-1Then we move to the next column of the second matrix.
1*3=3
-3*2=-6
-6+3=
-3Then the final column of the second matrix.
1*4=4
-3*3=-9
-9+4=-5
Our matrix so far:
![\left[\begin{array}{ccc}-1&-3&-5\\x&x&x\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%26-3%26-5%5C%5Cx%26x%26x%5Cend%7Barray%7D%5Cright%5D%20)
We do the same for the bottom row of the first matrix.
<em>First Column</em>
2*2=4
0*1=0
4+0=
4<em>Second Column
</em>2*3=6
0*2=0
6+0=
6
<em>Third Column</em>
2*4=8
0*3=0
8+0=
8Our final matrix is:
![\left[\begin{array}{ccc}-1&-3&-5\\4&6&8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%26-3%26-5%5C%5C4%266%268%5Cend%7Barray%7D%5Cright%5D)
:)
