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Iteru [2.4K]
2 years ago
11

Adog has a mass of 12 kg. What is its weight? Round your answer to the nearest whole number

Physics
1 answer:
love history [14]2 years ago
3 0

Answer:

26.5

Explanation:

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Eating pizza with friends after a football game is most likey an example of which food choice factors?
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time and cost

Explanation:they have to pay for the pizza and take time to eat it

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A wire has a diameter of 2. 0 mm and a length of 32 m, and is found to have a resistance of 1. 8 ω. what is the resistivity of t
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A wire has a diameter of 2. 0 mm and a length of 32 m and is found to have a resistance of 1. 8 ω having a resistivity of the wire

Resistivity, which is frequently denoted by the letter rho, is mathematically equal to the resistance R of a specimen, such as a wire, multiplied by its cross-sectional area A, and divided by its length l; it is represented by the symbol RA/l. The ohm is the unit of resistance.

A conductor's resistance (R) is inversely proportional to its length (L), with R L. We now know the variables that affect resistivity. Ohm's law and resistors have also been covered in relation to parallel formulae.

The resistance provided by the substance per unit length for unit cross-section is referred to as a conductor's resistivity. Temperature and pressure affect the material's resistivity, which is a property. When compared to the resistivity of insulators, conductors have a low resistivity.

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8 0
1 year ago
What's the thrust force of 20,000N
nika2105 [10]

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5 0
2 years ago
Kyle, a 95.0 kg football player, leaps straight up into the air (with no horizontal velocity) to catch a pass. He catches the 0.
babymother [125]

Answer:

The initial speed of the ball was 26.2 m/s

Explanation:

When the football player is in the air at his maximum height the vertical component of velocity is zero, To obtain the horizontal velocity when the player catches the ball we need to apply the linear momentum conservation theorem:

m_1*v_{o1}+m_2*v_{o2}=m_t*v_f\\0.430kg*(v)+m_2*(0)=mt*vt

we need to obtain the time taken to go down.

y=Y_o+v_o*t-\frac{1}{2}g*t^2\\\\0=0.589-4.9t^2\\solving:\\t_1=0.346s\\

We have a horizontal displacement and the time taken to stop, so:

v_f=\frac{d}{t}=\frac{0.0409m}{0.346s}=0.118m/s

so:

0.430kg*(v)+m_2*(0)=(m1+m2)*vt\\v=\frac{(95.0kg+0.430kg)*0.118m/s}{0.430kg}\\\\v=26.2m/s

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When a car moves up a hill with constant
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