All of the fallowing are possible sources of error in a scientific investigation exept for

To collect quantitative data, scientists use all of the following except

Sever21 [200]

"Quantitative" means "expressed in numbers". Quantitative data is information you collect by using measuring tools, and measuring things.

You can get it using rulers, scales, and stopwatches, but not by using descriptive categories.

8 0

3 years ago

Two rings of radius 5 cm are 20 cm apart and concentric with a common horizontal x-axis. The ring on the left carries a uniforml

Yanka [14]

Answer:

The electric field due to the right ring at a location midway between the two rings is $2.41\times10^{3}\ V/m$

Explanation:

Given that,

Radius of first ring = 5 cm

Radius of second ring = 20 cm

Charge on the left of the ring = +30 nC

Charge on the right of the ring = -30 nC

We need to calculate the electric field due to the right ring at a location midway between the two rings

Using formula of electric field

$E=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{qx}{(x^2+R^2)^{\frac{3}{2}}}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times30\times10^{-9}\times0.1}{((0.1)^2+(0.2)^2)^{\frac{3}{2}}}$

$E=2.41\times10^{3}\ V/m$

Hence, The electric field due to the right ring at a location midway between the two rings is $2.41\times10^{3}\ V/m$

3 0

3 years ago

Whoever answers this question will get brainliest and extra points! :)

ivolga24 [154]

Answer:

14. D

15. It is showing a magnet pushing against itself and everything around with tremendous force.

16. D, because of how many forcefields in that area.

17. It is showing (both) that they are attracting and repealing.

18. I’m not sure sorry :(

Explanation:

hope this helped!

6 0

3 years ago

Two boys, Shrijan having weight 600N and Shrijesh having weight

andreev551 [17]

Answer:

to be balanced moments should be equal

4m

Explanation:

$fd = fd \\ 600 \times 2 = 300 \times x \\ \frac{600 \times 2}{300} = x \\ 4m$

5 0

3 years ago

A convex refracting surface has a radius of 12 cm. Light is incident in air (n = 1) and refracted into a medium with an index of

OLga [1]

Answer:

<h2>36cm from the surface</h2>

Explanation:

Equation of refraction of a lens is expression according to the formula given below;

$\dfrac{n_2}{v} = \dfrac{n_1}{u}= \dfrac{n_2-n_1}{R}$

R is the radius of curvature of the convex refracting surface = 12cm

v is the image distance from the refracting surface

u is the object distance from the refracting surface

n₁ and n₂ are the refractive indices of air and the medium respectively

Given parameters

R = 12 cm

u = $\infty$ (since light incident is parallel to the axis)

n₁ = 1

n₂ = 1.5

Required

<em>focus point of the light that is incident and parallel to the central axis (v)</em>

<em />

Substituting this values into the given formula we will have;

$\dfrac{1.5}{v} - \dfrac{1}{\infty}= \dfrac{1.5-1}{12}\\\\\dfrac{1.5}{v} -0= \dfrac{0.5}{12}\\\\\dfrac{1.5}{v}= \dfrac{0.5}{12}\\\\$

Cross multiply

$1.5*12 = 0.5*v\\ \\18 = 0.5v\\\\v = \frac{18}{0.5}\\ \\v = 36cm$

Hence Light incident parallel to the central axis is focused at a point 36cm from the surface

6 0

3 years ago