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densk [106]
3 years ago
7

I need help to figure out how to solve this problem and solve it!!!

Physics
2 answers:
wariber [46]3 years ago
4 0

well it looks like the walk at a constant increasing pace then at a constant pace then increaseing pace then constant pace then they slow down then walk at a constant pace then walk at a constantly increasing pace

plz rate me  brainliest

8_murik_8 [283]3 years ago
4 0
This is actually more math than physics.

This is a graph of how far a shopper is from where she started, as time goes on.
Every point on the line is a point in time and space:  The number down below it
   shows how long it was after the beginning, and the number to the left of it shows
   the distance from the starting place.

Look along the bottom.  The graph only covers the first 100 seconds.
Look up along the left side.  The graph can only show distance that are
     30 meters or less from where she started.  If she gets farther away,
      the line will go up off the graph.  

Now, here are some things you're going to see on the graph:

-- When she's walking away from the cart pick-up, her distance from it
is increasing as time goes on.  So the line on the graph is rising.

-- When she's standing still in the store, her distance from the cart pick-up
isn't changing as time goes on.  So the line on the graph is flat.

-- When she's walking TOWARD where she started, her distance from it
is decreasing as time goes on.  So the line on the graph is dropping.

-- The faster she walks, the faster the distance changes, so the line is steeper.

Knowing this, you can look at the graph and see what happened:

-- She started some place when Time was zero.
    I call it picking up the shopping cart.

-- In the first 20 seconds, she walked 15 meters away from the carts.

-- Then she stood still for 10 seconds.

-- Then she walked away from the carts, faster, for another 10 seconds.
    Now she was 25 m from them. 

-- Then she stood still again for 10 seconds.

-- Then she turned around and walked back toward the carts for 10 seconds.
    At that time, she was only 20 m from where she started.

-- She stood still there for 10 seconds.

-- She turned again, and resumed walking away from where she started.
   She walked rather slowly for 30 seconds, and wound up 30m from
         where she started, 100 seconds after she left it.

That's all we know, because that's the end of the graph.

The question wants you to describe this motion.
When you write it up, please don't just copy my words.  Make it your own.
  
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The answer to ur question is B
8 0
3 years ago
The most common isotope of hydrogen contains a proton and an electron 'separated by about -11-27 5.0 x 10 m. The mass of proton
Brrunno [24]

Answer:

A)   F_g = 4.05 10⁻⁴⁷ N, B)   F_e = 9.2 10⁻⁸N, C)    \frac{F_e}{F_g} = 2.3 10³⁹

Explanation:

A) It is asked to find the force of attraction due to the masses of the particles

Let's use the law of universal attraction

            F = G \frac{m_1m_2}{r^2}

let's calculate

            F = 6.67 \ 10^{-11} \ \frac{9.1 \ 10^{-31} \ 1.67 \ 10 ^{-27} }{(5 \ 10^{-11})^2 }

            F_g = 4.05 10⁻⁴⁷ N

B) in this part it is asked to calculate the electric force

Let's use Coulomb's law

            F = k \  \frac{q_1q_2}{r^2}

let's calculate

            F = 9 \ 10^9 \  \frac{(1.6 \ 10^{-19} )^2}{(5 \ 10^{-11})^2}

             F_e = 9.2 10⁻⁸N

C) It is asked to find the relationship between these forces

        \frac{F_e}{F_g} = \frac{9.2 \ 10^{-8} }{4.05 \ 10^{-47} }

        = 2.3 10³⁹

therefore the electric force is much greater than the gravitational force

4 0
3 years ago
A parallel-plate air capacitor is made from two plates 0.210 m square, spaced 0.815 cm apart. it is connected to a 120 v battery
GuDViN [60]

Answer:

at the beginning: 2.3\cdot 10^{-10} F

when the plates are pulled apart: 1.1\cdot 10^{-10} F

Explanation:

The capacitance of a parallel-plate capacitor is given by

C=k \epsilon_0 \frac{A}{d}

where

k is the relative permittivity of the medium (for air, k=1, so we can omit it)

\epsilon_0 = 8.85\cdot 10^{-12} F/m is the permittivity of free space

A is the area of the plates of the capacitor

d is the separation between the plates

In this problem, we have:

A=0.210 m^2 is the area of the plates

d=0.815 cm=8.15\cdot 10^{-3} m is the separation between the plates at the beginning

Substituting into the formula, we find

C=(1)(8.85\cdot 10^{-12}F/m)\frac{0.210 m^2}{8.15\cdot 10^{-3} m}=2.3\cdot 10^{-10} F

Later, the plates are pulled apart to d=1.63 cm=0.0163 m, so the capacitance becomes

C=(1)(8.85\cdot 10^{-12}F/m)\frac{0.210 m^2}{0.0163 m}=1.1\cdot 10^{-10} F

4 0
3 years ago
"Force is applied to an object and the object is moved over a distance in the same direction of the applied force" is the defini
DaniilM [7]
I believe this is gravitational force

8 0
3 years ago
Read 2 more answers
What will it be ? Plz help me
IgorC [24]

Answer:

For number 2, it will be 8.

3 0
2 years ago
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