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3 years ago

8

Ben is exercising his pony on a large oval track. The long is trotting at a constant speed of 10 m/s around the track. Which sta

tement can be made about the pony's acceleration

1 answer:

nlexa [21]3 years ago

6 0

There is 0 acceleration because the pony is moving at a constant velocity

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The measured value of the speed of light is about 300,000 km/s. suppose a futuristic space train is traveling at 200,000 km/s wi

Gwar [14]

The speed of light generally would be 300000km/s but since the train is moving in the same direction as the light it would apparently appear to be 100000km/s

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3 years ago

object is placed 15cm in front of a plane mirror. If the mirror is moved further 5cm away from the object and the image is

solong [7]

Answer:

The image will most likely be 20cm in front the mirror since the mirror was placed further 5cm.

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2 years ago

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at the center of the neutral metal block, what is the direction of the electric field contributed by the charge in and on the me

elena-14-01-66 [18.8K]

The direction of electric field by the charge in and on the metal block will be along the direction line 5 as given in question.

<h3>How to determine electric field direction in a metal block?</h3>

The charge always remain on outer surface of metal and inside the metal block, the net electric field is zero. But due to dipole there is an electric field at the center of metal block i.e. at point R along direction line 1.

Now, to make make the net electric field zero at center, the electric field by the charge in and on the metal block must be equal in magnitude to that of electric field due to dipole at point R and in opposite direction to that of the net electric field at at R due to dipole.

The electric field by the charge in and on the metal block will be making 180° angle to the electric field due to dipole at point R.

Hence the direction of electric field by the charge in and on the metal block will be along the direction line 5 as given in question.

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11 months ago

A solid circular plate has a mass of 0.25 kg and a radius of 0.30 m. It starts rolling from rest at the top of a hill 10 m long

KATRIN_1 [288]

To solve the problem it is necessary to apply the equations related to the conservation of both <em>kinetic of rolling objects</em> and potential energy and the moment of inertia.

The net height from the point where it begins to roll with an inclination of 30 degrees would be

$h=Lsin30$

$h=10sin30$

$h=5m$

In the case of Inertia would be given by

$I = \frac{mR^2}{2}$

In general, given an object of mass m, an effective radius k can be defined for an axis through its center of mass, with such a value that its moment of inertia is

$I = mk^2$

$\frac{mR^2}{2}= mk^2$

$\frac{k^2}{R^2}=\frac{1}{2}$

Replacing in Energy conservation Equation we have that

Potential Energy = Kinetic Energy of Rolling Object

$mgh = \frac{1}{2}mv^2(1+\frac{k^2}{r^2})$

$9.8*5=\frac{1}{2}v^2(1+\frac{1}{2})$

$v^2 (1.5) = 98$

$v=8.0829m/s$

Therefore the correct answer is C.

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3 years ago

A 2300 kg truck has put its front bumper against the rear bumper of a 2400 kg SUV to give it a push. With the engine at full pow

IrinaK [193]

Answer:

a) $a_{max} = 3.8\,\frac{m}{s^{2}}$ , b) $F = 9260\,N$

Explanation:

a) The maximum possible acceleration that the truck can give to the SUV is:

$a_{max} = \frac{18,000\,N}{2,400\,kg+2300\,kg}$

$a_{max} = 3.8\,\frac{m}{s^{2}}$

b) The equation of equilibrium for the truck is:

$18,000\,N - F = (2,300\,kg)\cdot (3.8\,\frac{m}{s^{2}})$

The force of the SUV's bumper on the truck's bumper is:

$F = 9260\,N$

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3 years ago

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