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vaieri [72.5K]
3 years ago
11

A ball is thrown straight upward. When it has reached the highest point in its motion, and is momentarily stopped, its accelerat

ion is
Physics
1 answer:
Damm [24]3 years ago
7 0
Increased .....................
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If you have two uncertainties, and they are from two different sources and contribute to the uncertainty of a measurement, what
Darya [45]

The propagation errors we can find the uncertainty of a given magnitude is the sum of the uncertainties of each magnitude.

                           Δm = ∑  | \frac{dm}{dx_i} | \ \Delta x_i

Physical quantities are precise values ​​of a variable, but all measurements have an uncertainty, in the case of direct measurements the uncertainty is equal to the precision of the given instrument.

When you have derived variables, that is, when measurements are made with different instruments, each with a different uncertainty, the way to find the uncertainty or error is used the propagation errors to use the variation of each parameter, keeping the others constant and taking the worst of the  cases, all the errors add up.

If m is the calculated quantity, x_i the measured values ​​and Δx_i the uncertainty of each value, the total uncertainty is

                      Δm = ∑  | \frac{dm}{dx_i } | \ \Delta x_i    | dm / dx_i | Dx_i

               

for instance:

If the magnitude is  a average of two magnitudes measured each with a different error

                     m = \frac{m_1+m_2}{2}

                     Δm = | \frac{dm}{dx_1} |  Δx₁ + | \frac{dm}{dx_2} | Δx₂

                     \frac{dm}{dx_1} = ½

                     \frac{dm}{dx_2} = ½

                     Δm = \frac{1}{2} Δx₁ + ½ Δx₂

                     Δm = Δx₁ + Δx₂

In conclusion, using the propagation errors we can find the uncertainty of a given quantity is the sum of the uncertainties of each measured quantity.

Learn more about propagation errors here:

brainly.com/question/17175455

6 0
2 years ago
A proton initially has v=4.0i^−2.0j^+3.0k^ and then 4.0 s later has v=−2.0i^−2.0j^+5.0k^ (in meters per second). For that 4.0 s,
pishuonlain [190]

Answer:

a_{avg}=-1.5i+0.5k

1.58113883008\ m/s^2

-18.43^{\circ}\ or\ 161.57^{\circ}

Explanation:

u = 4.0i−2.0j+3.0k v = −2.0i−2.0j+5.0k

Average acceleration is given by

a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{-2-4, -2+2, 5-3}{4}\\\Rightarrow a=-1.5i-0j+0.5k

a_{avg}=-1.5i+0.5k

The magnitude is

a_{avg}=\sqrt{(-1.5)^2+0.5^2}\\\Rightarrow a_{avg}=1.58113883008\ m/s^2

The magnitude is 1.58113883008\ m/s^2

The angle is

\theta=tan^{-1}\dfrac{a_z}{a_x}\\\Rightarrow \theta=tan^{-1}\dfrac{0.5}{-1.5}\\\Rightarrow \theta=-18.43^{\circ}\ or\ 161.57^{\circ}

The angle between a_{avg} and the positive direction of the x axis is -18.43^{\circ}\ or\ 161.57^{\circ}

4 0
3 years ago
What occurs as a ray of light passes from<br> al inilo water?
iVinArrow [24]

Answer:

this may be wrong but I am not sure

3 0
3 years ago
the flame on a gas stove heats the bottom of a metal pot. (A) conduction (B)convection (C)radiation. the cold water in a metal p
Sedbober [7]
The flame on a gas stove heats the bottom of a metal pot is conduction.
The sun gives you a sunburn is a radiation
3 0
3 years ago
Read 2 more answers
A semi with a mass of 9,565 kg and going at a velocity of 55 m/s and hits a parked car(992 kg) at rest. If all the momentum is t
Katena32 [7]

Answer:

Speed of car, v₁ = 55 m/s

Explanation:

It is given that,

Mass of Semi, m₁ = 9565 kg

Initial velocity of semi, u₁ = 55 m/s

Mass of car, m₂ = 992 kg

Initial velocity of car, u₂ = 0 (at rest)

Since, the collision between two objects is elastic and all the momentum is transferred to the car i.e final speed of semi, v₂ = 0

Let the speed of the car is v₁. Using conservation of linear momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

9565\ kg\times 55\ m/s+992\ kg\times 0=9565\ kg\times v_1+0

v₁ = 55 m/s

Hence, the car move forward with a speed of 55 m/s.

3 0
3 years ago
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