Question

Ben walks 500 meters from his house to the corner store. He then walks back toward his house but stops to talk to a neighbor when he is 200 meters from the corner store. If it takes Ben 910 seconds from the time he leaves his house until he stops to talk to his neighbor, what is his average velocity? (Round your answer to the nearest tenth of a meter per second.) Ben’s average velocity is m/s.

Answer 1

Answer:0.33 m/s

Explanation:

Given

Ben walks towards corner stone which 500 m from his house

As he walk back he stop to talk his neighbor which is 200 m from corner stone

Average velocity of Ben is given by the ratio of his displacement and total time taken

Displacement of Ben is $=500-200=300\ m$

total time taken by Ben$=910\ s$

$v_{avg}=\frac{displacement}{time}$

$v_{avg}=\frac{300}{910}$

$v_{avg}=0.33\ m/s$

Answer 2

Answer:

0.33

Explanation: