Answer:
S = V0 t + 1/2 a t^2
S = 5 m/s * 300 s + 1/2 * 1.2 m/s * (300 s^2)
S = 1500 m + .6 * 90000 m = 55,500 m
Check: V0 = 5 m/s
V2 = V0 + a t = 5 + 1.2 * 300 = 365 m/s
Vav = (V1 + V2) / 2 = (5 + 365) / 2 = 185 m/s (note uniform motion)
S = 185 * 300 = 55,500 m
We calculated V2 above at 365 m/s the speed after 300 sec
Answer:
Dy = 111.66 [m]
t = 3.5 [s]
Explanation:
To solve this problem we must use the equations of kinematics.

where:
Vf = final velocity [m/s]
Vo = initial velocity = 27 [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time = 3.5 [s]
Note: The negative sign of the equation means that the gravity acceleration goes in opposite direction
Vf = 27 - (9,81*3,5)
Vf = - 7.33 [m/s] (this negative sign indicates that at this moment the snowball is going downwards)
To find how high the snowball was we must use the following equation:

Dy = (27*3.5) + (0.5*9.81*3.5)
Dy = 94.5 + (17.16)
Dy = 111.66 [m]
I think its the car moving to a stop sign