Answer:
95.3g
Explanation:
Given parameters:
Mass of water = 540g
Percentage by mass of solution = 15%
Unknown:
Mass of sucrose = ?
Solution;
To solve this problem, we must understand that a solution is made up of solute dissolved in a solvent. A solute is the solid dissolved in another. The solvent is the is dissolving medium;
Percentage by mass of solute in solution = ![\frac{Mass of solute}{Mass of solution} x 100](https://tex.z-dn.net/?f=%5Cfrac%7BMass%20of%20solute%7D%7BMass%20of%20solution%7D%20%20x%20100)
Mass of solution = mass of water + Mass of sucrose = 540 + M
where M is the mass of sucrose;
therefore;
= 15
Solving for M gives 95.3g
Mass of sucrose is 95.3g
This would be a social hierachy
Answer:
Amount of sodium sulphate is 5.64g
Amount of water is 1.017g
Explanation:
First give a balanced equation for the reaction
2NaOH + H2SO4 > Na2SO4 + 2H2O
Find the number of moles of each reacting specie by dividing the mass by their molar mass
Use the number of moles to find the amount in the product
For 2NaOH
2.26/80=0.02825moles
0.02825 x molar mass of 2H2O = 1.017g
For H2SO4
4.19/98=0.0428moles
0.0428 x 132 = 5.64g
6.022*10^23 is the number