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3 years ago

1. According to the equation, what mass of hydrogen fluoride is necessary to produce 2.3 g of sodium fluoride?

Chemistry

1 answer:

Vanyuwa [196]3 years ago

4 0

Answer:

1.096g

Explanation:

You must know the atomic mass of Hydrogen, Fluorine, and Sodium before you can start:

Hydrogen: 1.008g/mol

Fluorine: 18.99g/mol

Sodium: 22.98g/mol

Next, find the composition percentage of NaF

22.98 + 18.99 = 41.97

Fluorine is 18.99/41.97 =45.25%

Sodium is 100-45.25 = 54.75%

Ultimately we want to know about HF so find how much F is in 2.3g: 2.3 * 0.4525 = 1.041g

Find comp. percentage of HF

18.99+1.008 = 19.998; H/total F/total

Hydrogen 5.041%

Fluorine 94.959%

Laws of conservation of say we have 1.041g of fluorine in our HF. We know 1.041 is 94.959% of the mass of HF so do some simple math to find the remaining: 1.041/0.94959 = 1.096g

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A 1.24g sample of a hydrocarbon, when completely burned in an excess of O2 yields 4.04g Co2 and 1.24g H20. Draw plausible struct

arsen [322]

Answer:

Plausible structure has been given below

Explanation:

Molar mass of $CO_{2}$ is 44 g/mol and molar mass of $H_{2}O$ is 18 g/mol
Number of mole = (mass/molar mass)

4.04 g of $CO_{2}$ = $\frac{4.04}{44}moles$ $CO_{2}$ = 0.0918 moles of $CO_{2}$

1 mol of $CO_{2}$ contains 1 mol of C atom

So, 0.0918 moles of $CO_{2}$ contains 0.0918 moles of C atom

1.24 g of $H_{2}O$ = $\frac{1.24}{18}moles$ $H_{2}O$ = 0.0689 moles of $H_{2}O$

1 mol of $H_{2}O$ contain 2 moles of H atom

So, 0.0689 moles of $H_{2}O$ contain $(2\times 0.0689)moles$ of $H_{2}O$ or 0.138 moles of $H_{2}O$

Moles of C : moles of H = 0.0918 : 0.138 = 2 : 3

Empirical formula of hydrocarbon is $C_{2}H_{3}$

So, molecular formula of one of it's analog is $C_{4}H_{6}$

Plausible structure of $C_{4}H_{6}$ has been given below.

4 0

3 years ago

PLEASE HELP!! 40 POINTS

PSYCHO15rus [73]

Answer:

1) 6.524779402×10^(-17)

2)521.1g

3)113

Explanation:

5 0

2 years ago

Read 2 more answers

Which of the Atoms shown has an atomic number four

dimulka [17.4K]

Answer:

Explanation:

Atomic # = Protons

it says 4 p in the inside of the orbital

4 0

3 years ago

Calculate the volume of 1M NaOH required to neutralize 200 cc of 2M HCI. What mass of sodium

Nezavi [6.7K]

NaOH+HCl-> NaCl+H2O

1 mole of NaOH

1 mole of HCl.

To calculate volume of NaOH

CaVa/CbVb= Na/Nb

Where Ca=2M

Cb=1M

Va=200cm³

Vb=xcm³

Substitute into the equation.

2×200/1×Vb=1/1

400/Vb=1/1

Cross multiply

Vb×1=400×1

Vb=400cm³

To calculate the mass of sodium chloride, NaCl from the neutralization rxn.

Mole of NaCl=1

Molar mass of NaCl= 23+35.5=58.5

Mass=xgrammes.

Mass of NaCl=Number of moles × Molar mass.

Substitute

Mass of NaCl= 1×58.5

=58.5g

This is what I could come up with.

5 0

3 years ago

HELP! THIS IS A TIMED QUIZ!!

ivanzaharov [21]

Answer:

A) Age!! Its because even if the object was 1 year old or 100 years old, nothing about the impact would change. However, those other categories depict features that would definitely make an impact. For example as object that is big, fast, and hits at an angle perpendicular to whatever it is moving towards, the impact will be very lage. But if its the opposite and it was small and slow, then the impact crater would not be as large. Good luck on your quiz!!

5 0

2 years ago