Answer:
Thank you
Explanation:
That made my day. I will make sure to pass it on.
Answer:
lol i think it would be cheaper to but a ticket or drive there
The output of the program is 10.
def mult(a, b = 1, c = 1):
print(a * b * c)
mult(2, 5)
<h3>Code explanation:</h3>
The code is written in python.
- A function is declared named "multi" and the function has parameter of a, b and c. The default value of b and c are 1.
- Locally, we print the product of a, b and c.
- Finally, we call the function with its inputted parameters. Notice we only had 2 argument while calling the function. This simply implies that the default value for c is used. Therefore, we will have 2 × 5 × 1 = 10
learn more on python here: brainly.com/question/22796383
Please provide the language you're using when you ask for programming help, otherwise you aren't going to get the answer that you are looking for.
Here it is in Java, and I'm assuming the number is given via user input? Otherwise, just remove the user input function and replace the integer with a value of your choice. Note, that this isn't the full code; only what is relevant to the question.
public static void main(String[] args) {
int num = numInput(10);
printDoubles(num, 100); // You can create a user input function for
// maxValue if you wanted to.
}
/**
* Receives user input between 0 and the absolute value of maxInput.
* @param maxInput The largest absolute value that can be input.
*/
private static int numInput(int maxInput) {
Scanner sc = new Scanner(System.in);
maxInput = Math.abs(maxInput);
int num = 0;
while (!(num > 0 && num <= maxInput)) {
num = sc.nextInt();
if (!(num > 0 && num <= maxInput)) {
System.out.println("Input too small or too large");
}
}
return num;
}
/**
* Continues to print out num doubled until maxValue is reached.
* @param num The number to be printed.
* @param maxValue The maximum value (not including in which num can be doubled to.
*/
private static void printDoubles(int num, int maxValue) {
if (num >= maxValue) {
System.out.println("No output.");
}
while (true) {
if (num >= maxValue) {
break;
}
if (num < maxValue) {
System.out.print(num + " ");
}
num *= 2;
}
System.out.println();
}
Answer:
Please find the attached file for the complete solution:
Explanation:
