we know that
<u>case a)</u> ∠ABC
The geometric figure is not drawn in the diagram
<u>case b)</u> ∠BCE
The geometric figure is drawn in the diagram
<u>case c)</u> line segment CA
The geometric figure is drawn in the diagram
<u>case d)</u> Ray CA
The geometric figure is drawn in the diagram
<u>case e)</u> Circle C
The geometric figure is drawn in the diagram
<u>case f)</u> Ray BE
The geometric figure is not drawn in the diagram
<u>case g)</u> LIne segment AE
The geometric figure is not drawn in the diagram
see the attached figure to better understand the problem
<h2>
Answer with explanation:</h2>
It is given that:
f: R → R is a continuous function such that:
∀ x,y ∈ R
Now, let us assume f(1)=k
Also,
( Since,
f(0)=f(0+0)
i.e.
f(0)=f(0)+f(0)
By using property (1)
Also,
f(0)=2f(0)
i.e.
2f(0)-f(0)=0
i.e.
f(0)=0 )
Also,
i.e.
f(2)=f(1)+f(1) ( By using property (1) )
i.e.
f(2)=2f(1)
i.e.
f(2)=2k
f(m)=f(1+1+1+...+1)
i.e.
f(m)=f(1)+f(1)+f(1)+.......+f(1) (m times)
i.e.
f(m)=mf(1)
i.e.
f(m)=mk
Now,
Also,
i.e. 
Then,
(
Now, as we know that:
Q is dense in R.
so Э x∈ Q' such that Э a seq 
belonging to Q such that:
)
Now, we know that: Q'=R
This means that:
Э α ∈ R
such that Э sequence 
such that:
and
( since belongs to Q )
Let f is continuous at x=α
This means that:
This means that:
This means that:
f(x)=kx for every x∈ R
Answer:
28.26metres
Step-by-step explanation:
3-radius
diameter- radius time 2
diameter - 9
"lengh of edge"= curcomphrence
c= diameter times 3.14
c=28.26
