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ddd [48]
3 years ago
14

Which of these is a ball and stick model?

Chemistry
2 answers:
Tanzania [10]3 years ago
7 0

Answer:

say she in love with me say she just want compuny].

Explanation:

enyata [817]3 years ago
4 0

Answer:

The answer is C

Explanation:

I just answered on edgenuity <3

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in a typical person, the level of glucose is about 85 mg/ 100 mL of blood. if an average body contains about 11 pt of blood, how
Vanyuwa [196]

Let's note that 1 pint = 473.1765 mL, so 11 pints should be 5204.9415 mL.

We make a proportion out of the word problem

(85 mg glucose/ 100 mL) times (1 g/ 1000 mg) = 4.4242 grams of glucose

5 0
3 years ago
How would you compare/contrast energy with system
Lelechka [254]

Answer:

See which of your answer choices are comparable and what you can contrats them with

Explanation:

YEET

5 0
3 years ago
What is the mass of silver (107.87 g/mol) produced by the reaction of 3.00 moles of copper with 3.00 moles of silver nitrate?Cu
vladimir2022 [97]

Answer: 323.61 g of Ag will be produced

Explanation:

The given balanced chemical reaction is :

Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag

According to stoichiometry :

2 moles of AgNO_3 require 1 mole of Cu

Thus 3.00 moles of  AgNO_3 will require=\frac{1}{2}\times 3.00=1.50moles  of Cu

Thus AgNO_3 is the limiting reagent as it limits the formation of product.

As 2 moles of AgNO_3 give =  2 moles of Ag

Thus 3.00 moles of AgNO_3 give =\frac{2}{2}\times 3.00=3.00moles  of Ag

Mass of Ag=moles\times {\text {Molar mass}}=3.00moles\times 107.87g/mol=323.61g

Thus 323.61 g of Ag will be produced from the given moles of both reactants.

3 0
3 years ago
6 C + 3 H2 -&gt; C3H6, \Delta Δ ΔH= 49 kJ If 8.2 moles of C react with excess H2, what is the total change in energy?
Delicious77 [7]

I would like to know too

5 0
3 years ago
When 125.0 g of ethylene (C2H4) burns in 60.0 grams of oxygen to give carbon dioxide and water, how many grams of CO2 are formed
gizmo_the_mogwai [7]

Answer:

             66 g of CO₂

Solution:

The Balance Chemical Reaction is as follow,

                             C₂H₂  +  5/2 O₂    →    2 CO₂  +  H₂O

Or,

                             2 C₂H₂  +  5 O₂    →    4 CO₂  +  2 H₂O    -------  (1)

Step 1: Find out the limiting reagent as;

According to Equation 1,

            56.1 g (2 mole) C₂H₂ reacts with  =  160 g (5 moles) of O₂

So,

                  125 g of C₂H₂ will react with  =  X g of O₂

Solving for X,

                      X =  (125 g × 160 g) ÷ 56.1 g

                      X =  356.5 g of O₂

It means for total combustion of Ethylene we require 356.5 g of O₂, but we are only provided with 60.0 g of O₂. Therefore, O₂ is the limiting reagent and will control the yield.

Step 2: Calculate Amount of CO₂ produced as;

According to Equation 1,

              160 g (5 mole) O₂ produces  =  176 g (4 moles) of CO₂

So,

                  60.0 g of O₂ will produce  =  X g of CO₂

Solving for X,

                      X =  (60.0 g × 176 g) ÷ 160 g

                      X =  66 g of CO₂

8 0
3 years ago
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