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makkiz [27]
3 years ago
11

A clay ball (50 degrees Fahrenheit) is placed in a bucket of water (80 degrees Fahrenheit.) which scenario describes how heat en

ergy is transferred between the ball and water?
a.) heat energy is transferred from the ball to the water until they are both at 65 degrees Fahrenheit.

b.) heat energy is transferred from the water to the ball until they are both at 65 degrees Fahrenheit.

c.) heat energy is transferred from the water to the ball until the ball is at 80 degrees Fahrenheit and the water is at 50 degrees Fahrenheit.

d.) no heat energy would be transferred between the ball and the water, so the ball will stay at 50 degrees Fahrenheit and the water will stay at 80 degrees Fahrenheit.
Chemistry
2 answers:
Readme [11.4K]3 years ago
6 0

Answer:

c

Explanation:

pashok25 [27]3 years ago
3 0

Answer:

b

Explanation:

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NEED IT ASAP!PLEASE HURRY
marin [14]

Answer:

snow, or freezing rain?

Explanation:

because freezing rain can occur then, but snow is more common.

7 0
2 years ago
A sample of hydrogen was collected by water displacement at 23.0°C and an atmospheric pressure of 735 mmHg. Its volume is 568 mL
ziro4ka [17]

Answer:

V = 552 mL or 0.552 L

Explanation:

First, we need to calculate the number of moles of H2 using the ideal gas equation which is:

PV = nRT

Solving for n:

n = PV / RT

Where:

P = Pressure

V = Volume

R = Gas constant (0.082 L atm / K mol)

T = Temperature in K

Let's convert first both pressure in atm, remember that 1 atm = 760 mmHg

P = 735 / 760 = 0.967 atm

Pwater = 21 / 760 = 0.028 atm

Finally temperature to Kelvin:

T = 23 + 273.15 = 296.15 K

Now, at first the hydrogen was collected by water displacement so pressure is:

P = 0.967 - 0.028 = 0.939 atm

Now the moles of hydrogen:

n = 0.939 * 0.568 / 0.082 * 296.15

n = 0.022 moles

Now that we have the moles, let's calculate the volume when the pressure is 735 mmHg

V = nRT/P

V = 0.022 * 0.082 * 296.15 / 0.967

V = 0.552 L or 552 mL

This is the volume that hydrogen occupies.

6 0
2 years ago
How long, in seconds, would it take for the concentration of A to decrease from 0.860 M to 0.310 M?
kogti [31]

Answer:

2.038 seconds.

Explanation:

So, in the question above we are given the following parameters in order to solve this question. We are given a rate constant of 0.500 s^-, initial concentration= 0.860 M and final concentration= 0.310 M,the time,t =??.

Assuming that the equation for the first order of reaction is given below,that is;

A ---------------------------------> products.

Recall the formula below;

B= B° e^-kt.

Therefore, e^-kt = B/B°.

-kt = ln B/B°.

kt= ln B°/B.

Where B° and B are the amount of the initial concentration and the amount of the concentration remaining, k is the rate constant and t = time taken for the concentration to decrease.

So, we have; time taken,t = ln( 0.860/.310)/0.500.

==> ln 2.77/0.500.

==> time taken,t =2.038 seconds.

6 0
3 years ago
The atomic mass of seven atoms of antimony is ?
son4ous [18]

Answer:

Percent composition by element

Element Symbol Atomic Mass

Antimony Sb 121.760

Explanation:

6 0
2 years ago
Under what pressure did 10L of gas change to if the original pressure was 4 atm on 3L?​
cluponka [151]

Answer:

11111

Explanation:

1110001001

3 0
3 years ago
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