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Alla [95]
3 years ago
9

A spring with a mass on the end of it hangs in equilibrium a distance of 0.420 m above the floor. The mass is pulled down a dist

ance of 0.060 m below the original position, released, and allowed to oscillate. How high above the floor is the mass at the highest point in its oscillation?
Physics
1 answer:
yanalaym [24]3 years ago
4 0

Answer:

the highest point above the ground = 0.48 m

Explanation:

lets ignore air friction, spring details,

The rest mass hanges 0.42 m above the floor and you pull 0.06 m below the original position, this is done by putting energy into the stratched spring so that when released the mass will compress the spring and cover a distance 0.06 m above the rest height.

then the highest point the mass will attain is 0.42 m + 0.06 m = 0.48 m above the ground.

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A parallel-plate capacitor is held at a potential difference of 250 V. A proton is fired toward a small hole in the negative pla
MissTica

Answer:

The speed of proton when it emerges through the hole in the positive plate is 2.05\times 10^5\ m/s.

Explanation:

Given that,

A parallel-plate capacitor is held at a potential difference of 250 V.

A A proton is fired toward a small hole in the negative plate with a speed of, u=3\times 10^5\ m/s

We need to find the speed when it emerges through the hole in the positive plate. It can be calculated using the conservation of energy as :

qV=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2\\\\1.6\times10^{-19}\times250=\dfrac{1}{2}mv^2-\frac{1}{2}\cdot1.67\times10^{-27}\cdot(3\times10^{5})^{2}\\\\\dfrac{1}{2}mv^2=3.515\cdot10^{-17}\\\\v=\sqrt{\dfrac{3.515\cdot10^{-17}\cdot2}{1.67\times10^{-27}}}\\\\v=2.05\times 10^5\ m/s

So, the speed of proton when it emerges through the hole in the positive plate is 2.05\times 10^5\ m/s.

5 0
3 years ago
A baseball (m=140g) traveling 32m/s moves a fielders
posledela

Answer:

Average force, F = 286.72 N

Explanation:

Given that,

Mass of the baseball, m = 140 g = 0.14 kg

Speed of the ball, v = 32 m/s

Distance, h = 25 cm = 0.25 m

We need to find the average  force exerted by the ball on the glove. It is solved using the conservation of energy as :

\dfrac{1}{2}mv^2=mgh

F = mg

\dfrac{1}{2}mv^2=Fh

F=\dfrac{mv^2}{2h}

F=\dfrac{0.14\times (32)^2}{2\times 0.25}

F = 286.72 N

So, the average force exerted by the ball on the glove is 286.72 N. Hence, this is the required solution.

7 0
3 years ago
A Perspex container has a 6 cm square base and contains
crimeas [40]

Answer:

a) V = 252 cm³

b) Vs = 72 cm³

Explanation:

a)

The volume of the water can be given by the following formula:

Volume\ of\ Water = V = (Base\ Area)(Height)\\V = (Length)^2(Height)\\V = (6\ cm)^2(7\ cm)\\

<u>V = 252 cm³</u>

<u></u>

b)

The volume of stone can be given by the change in volume of the water when the stone is dipped into it.

Volume\ of\ Stone = Vs = (Length)^2(Change\ in\ Height\ of\ Water)\\Vs = (6\ cm)^2(9\ cm - 7\ cm)\\

<u>Vs = 72 cm³</u>

6 0
3 years ago
A 500 N weight sits on the small piston of a hydraulic machine. The small piston has area 2.0 cm2. If the large piston has area
Ghella [55]

Answer:

d. 10000N

Explanation:

When a force (F_1) is exerted on the smaller area piston (A_1), the pressure that originates therein is transmitted to the larger area piston(A_2). According to Pascal's principle the pressure on the smallest piston (P_1=\frac{F_1}{A_1}) will be equal to the pressure on the largest piston (P_2=\frac{F_2}{A_2}):

\frac{F_1}{A_1}=\frac{F_2}{A_2}\\F_2=F_1\frac{A_2}{A_1}\\F_2=500N\frac{40cm}{2cm}\\F_2=10000N

7 0
3 years ago
Unlike acceleration and velocity, speed does not need to specify
frosja888 [35]

Unlike acceleration and velocity, speed does not need to specify the direction of motion. Speed is a scalar quality.

4 0
3 years ago
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