Answer:
0.076 J/gºC.
Explanation:
From the question given above, the following data were obtained:
Mass (M) of object = 1.32 kg
Heat (Q) released = –1.95 kJ
Change in temperature (ΔT) = –19.5°C (decrease in temperature)
Specific heat capacity (C) =?
Next, we shall convert 1.32 kg to grams (g). This can be obtained as follow:
1 kg = 1000 g
Therefore,
1.32 kg = 1.32 kg × 1000 g / 1 kg
1.32 kg = 1320 g
Next, we shall convert –1.95 kJ to joule (J). This can be obtained as follow:
1 kJ = 1000 J
Therefore,
–1.95 kJ = –1.95 kJ × 1000 / 1 kJ
–1.95 kJ = –1950 J
Finally, we shall determine the specific heat capacity of the object. This can be obtained as follow:
Mass (M) of object = 1320 g
Heat (Q) released = –1950 J
Change in temperature (ΔT) = –19.5°C (decrease in temperature)
Specific heat capacity (C) =?
Q = MCΔT
–1950 = 1320 × C × –19.5
–1950 = –25740 × C
Divide both side by –25740
C = –1950 / –25740
C = 0.076 J/gºC
Thus, the specific heat capacity of the object is 0.076 J/gºC.
