The 2nd one I think but I need some points
Answer:
F. 2NO + 02 —> 2NO
H. 4NH3 + 502 —> 4NO + 6H20
Explanation:
The law of conservation of mass states that matter can neither be created nor destroyed during a chemical reaction but can be convert from one form to another.
2NO + 02 —> 2NO
From the above, the total number of N on the left balance the total number on the right i.e 2 atoms of N on both side of the equation.
The total number of O on the left balance the total number on the right i.e 2 atoms of O on both side of the equation. This is certified by the law of conservation of mass.
4NH3 + 502 —> 4NO + 6H20
From the above, the total number of N on the left balance the total number on the right i.e 4 atoms of N on both side of the equation.
The total number of O on the left balance the total number on the right i.e 10 atoms of O on both side of the equation.
The total number of H on the left balance the total number on the right i.e 12 atoms of O on both side of the equation.
This is certified by the law of conservation of mass.
The rest equation did not conform to the law of conservation of mass as the atoms on the left side did not balance those on the right side
Because copper sulphate is not an ionic substance, no bonds are changed when it is dissolved. Thus it has to be a physical change
Answer:
1. Option A. Beta decay minus 0 -1e
2. Option B. Alpha 4 2He
3. Option A. Beta decay minus 0 -1e
Explanation:
1. 66 29Cu is undergoing beta decay minus since it produces a daughter nuclei having the same mass number and the atomic number increased by 1 i.e 66 30Zn
2. 238 92U is undergoing alpha decay since the daughter nuclei produced has a decrease of 4 in the mass number and a decrease of 2 in the atomic number ie 234 90Th
3. 14 6C is undergoing beta decay minus since the daughter nuclei produced has the same mass number and the atomic number increased by 1 i.e 14 7N
Please see the attached photo for more details
Answer:
The net chemical equation is: 6 H2O(g) + C3H8(g) → 10 H2(g) + 3 CO2(g)
Explanation:
First equation:
The reactants propane and water react to form the products CO and H2
C3H8(g) + 3H2O(g) → 3CO(g) + 7H2(g)
Second equation:
The products CO and H2 will react
CO(g) + H2O(g) → H2(g) + CO2(g)
We should multiply the equation by 3 (to equal the products of the first equation)
3CO(g) + 3H2O(g) → 3H2(g) + 3CO2(g)
Add the second to the first equation:
C3H8(g) + 3 H2O(g) + 3 CO(g) + 3 H2O(g) → 3 H2(g) + 3CO2(g) + 3 CO(g) + 7 H2(g)
The net chemical equation is: 6 H2O(g) + C3H8(g) → 10 H2(g) + 3 CO2(g)
