Answer:
<em>The ball will go as high as 8.46 m</em>
Explanation:
<u>Projectile Motion</u>
It's the type of motion that experiences an object launched at a certain height above the ground and moves along a curved path exclusively under the action of gravity.
Being vo the initial speed of the object, θ the initial launch angle, and g the acceleration of gravity, then the maximum height hm can be calculated as follows:
The soccer ball is kicked at a speed of vo=24 m/s at an angle of θ=31°. Taking the value of 
, then:
The ball will go as high as 8.46 m
Answer:
Ng = 0.893 N, Ne = 0.107N
Explanation:
Number of particles in Ground state = Ng
Number of particles in Excited state = Ne
Ne/Ng = e^{(-ΔE)/kt}
Since excited state is 3 fold degenerate
Ne/Ng =3 x e^{(-ΔE)/kt}
ΔE = Energy difference between ground and excited states = 0.25eV
T = 960 K
Constant k = 8.617 x 10^-5 eV/K
Ne/Ng = 3 x e^{-0.25/(8.617x10^-5) x 960}
= 3 x e^(-3.188645)
= 3 x 0.0412 = 0.1237 ≅ 0.12
Ne = 0.12 Ng
but Ne + Ng = N, where is N is total number of particles, substituting Ne into equation we get,
Ng(1 + 0.12) = N
Ng = N/1.12 = 0.893N
and Ne = 0.12 x 0.893 N = 0.107 N
Answer:
Sedimentary
Explanation:
The process by which rock fragments are moved from the source is Sedimentary.
Answer:
The correct option is;
B. Object X travels at -2 m/s and object Y travels at 4 m/s after the spring is no longer compressed
Explanation:
The given parameters are;
The mass of object Y = M
The mass of object X = 2·M
The initial velocity of object X and object Y = 0 m/s
Let A represent the velocity of object X after the spring is released and B represent the velocity of object Y after the spring is released, therefore, by the principle of the conservation of linear momentum, we have;
(M + 2·M) × 0 = M × B + 2·M × A
∴ (M + 2·M) × 0 = 0 = M × B + 2·M × A
M × B = -2·M × A
∴ B = -2·A
Therefore, the velocity of the object Y = -2 × The velocity of the object X
Whereby the velocity of the object X = -2, The velocity of the object Y = -2 × -2 = 4
Which gives, object X travels at -2 m/s and object Y travels at 4 m/s after the spring is no longer compressed.
