Question

On a coordinate plane, triangle A B C and parallelogram G H J K are shown. Triangle A B C has points (2, 0), (1, negative 6), (negative 2, negative 4). Parallelogram G H J K has points (0, 0), (1, 2), (negative 2, 4), and (negative 3, 2). How does the area of triangle ABC compare to the area of parallelogram GHJK? The area of △ABC is 2 square units greater than the area of parallelogram GHJK. The area of △ABC is 1 square unit greater than the area of parallelogram GHJK. The area of △ABC is equal to the area of parallelogram GHJK. The area of △ABC is 1 square unit less than the area of parallelogram GHJK.

Answer 1

Answer:

The area of △ABC is 2 square units greater than the area of parallelogram GHJK.

Step-by-step explanation: