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yan [13]
3 years ago
6

A sled slides along a horizontal surface for which the coefficient of kinetic friction is 0.25. Its velocity at point A is 8.0 m

/s and at point B is 5.0 m/s. Use the impulse-momentum theorem to find how long the sled takes to travel from A to B.
Physics
1 answer:
muminat3 years ago
7 0

sled takes 1.22 seconds to travel from A to B.

<u>Explanation:</u>

impulse = change in momentum

Force \times time = mass 2 \times velocity 2(vf) - mass 1 \times velocity 1(vo)

F \times t = m(vf - vo)

F \times u \times t = m(vf - vo)

mg \times u \times t = m(vf - vo)    ( F = mg)

g \times u \times t = vf - vo

t = \frac{vf -vo}{g \times u}

t = \frac{(8 - 5)}{(9.8 \times 0.25)}

t = 1.22 s

t = 1.22 seconds.

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Each person is 80kg. 320/4
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4 years ago
If a rock climber accidentally drops a 77.5-g piton from a height of 215 meters, what would its speed be just before striking th
Viktor [21]

Let us list out what we know from the question.

Initial Velocity V_{i}  = 0 since the piton is 'dropped'.

Vertical Displacement of the piton D = 215 m

Acceleration due to gravity a = 9.8 m/s^{2}

Final Velocity V_{f} = ?

Using the equation, V^{2} _{f} = V^{2} _{i}  + 2aD and plugging in the known values, we get

V^{2} _{f}  = 0^{2}  + 2(9.8)(215)

Simplifying by taking square-root on both sides gives us V_{f} =  64.915 m/s

Thus, the speed of the piton just before striking the ground is 65 m/s.

4 0
3 years ago
In a vacuum, two particles have charges of q1 and q2, where q1 = +3.11 μC. They are separated by a distance of 0.241 m, and part
lesya [120]

Answer:

Charge of particle 2, q_2=-7.13\ \mu C

Explanation:

Given that,

Charge 1, q_1=3.11\ \mu C=3.11\times 10^{-6}\ C

The distance between charges, r = 0.241 m

Force experienced by particle 1, F = 3.44 N

We need to find the magnitude of electric charge 2. It can be calculated using formula of electrostatic force. It is given by :

F=k\dfrac{q_1q_2}{r^2}

q_2=\dfrac{Fr^2}{kq_1}

q_2=\dfrac{3.44\times (0.241)^2}{9\times 10^9\times 3.11\times 10^{-6}}

q_2=7.13\times 10^{-6}\ C

or

q_2=7.13\ \mu C

So, the magnitude of electric charge 2 is q_2=7.13\ \mu C. Since, the force is attractive then the magnitude of charge 2 must be negative.

5 0
3 years ago
Identify properties of a human body system
IceJOKER [234]

Answer:

integumentary, skeletal, muscular, nervous, endocrine, cardiovascular, lymphatic, respiratory, digestive, urinary, and reproductive

Explanation:

and this is biology not physics

5 0
3 years ago
A woman drives a car from one city to another with different constant speeds along the trip. She drives at a speed of 80.0 km/h
romanna [79]

Answer:

Total distance traveled= 75.36km (point at which she reaches her destination.)

Explanation:

With the speed and time data we can calculate the distance traveled on each path, but first we must transform the time units from minutes to hours:

First ride:

v=80km/h     t=25min*1h/60min=0.42h

distancie= v*t = 80km/h * 0.42h =33.6km

Second ride:

v=65.0km/h   t= 20min*1h/60min= 0.33h

distance= 65.0km/h*0.33h=21.67km

Stop: 60min= 1h  distance=0km

third ride:

v= 40.0km/h   t= 30.0min *1h/60min= 0.5h

distance= 40.0km/h*0.5h=20km

Total distance traveled= 33.6km +21.76km+20km

Total distance traveled= 75.36km

8 0
4 years ago
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