In the presence of sulfuric acid, this alcohol is dehydrated to form an alkene through an E1 mechanism. In the box, draw the maj
or alkene product of this reaction.
1 answer:
Answer:
figure is attached
Explanation:
When we treat alcohol with H₂SO₄ we get elimination as the major product.
As we can see in the given reaction that in step 1 the lone pair of electrons of oxygen attached to the alcohol make a bond with the hydrogen of H₂SO₄.
In the 2nd step H₂O gets detached from the parent ring which generated a positive charge on the ring.
In the 3rd step elimination of hydrogen from the carbon next to the carbonium carbon results into formation of an alkene.
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<u>Answer:</u>
<u>For a:</u> The balanced equation is
<u>For c:</u> The balanced equation is
<u>Explanation:</u>
A balanced chemical equation is one where all the individual atoms are equal on both sides of the reaction. It follows the law of conservation of mass.
- <u>For (a):</u>
The given unbalanced equation follows:
To balance the equation, we must balance the atoms by adding 2 infront of both and
and 3 in front of
For the balanced chemical equation:
- <u>For (b):</u>
The given balanced equation follows:
The given equation is already balanced.
- <u>For (c):</u>
The given unbalanced equation follows:
To balance the equation, we must balance the atoms by adding 2 infront of
For the balanced chemical equation:
- <u>For (d):</u>
The given balanced equation follows:
The given equation is already balanced.