In the presence of sulfuric acid, this alcohol is dehydrated to form an alkene through an E1 mechanism. In the box, draw the maj
or alkene product of this reaction.
1 answer:
Answer:
figure is attached
Explanation:
When we treat alcohol with H₂SO₄ we get elimination as the major product.
As we can see in the given reaction that in step 1 the lone pair of electrons of oxygen attached to the alcohol make a bond with the hydrogen of H₂SO₄.
In the 2nd step H₂O gets detached from the parent ring which generated a positive charge on the ring.
In the 3rd step elimination of hydrogen from the carbon next to the carbonium carbon results into formation of an alkene.
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Answer:- There are moles.
Solution:- It is a unit conversion problem where we are asked to convert mg of aspartame to moles. Aspartame is and it's molar mass is 294.31 grams per mole.
mg are converted to grams and then the grams are converted to moles as:
= moles of aspartame
So, there would be moles of aspartame in 1.00 mg of it.