1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
prisoha [69]
3 years ago
8

Name the following chemical compound. B2H6

Chemistry
2 answers:
Mila [183]3 years ago
6 0
The Compound name would be: "Diborane" 

Hope this helps!
timama [110]3 years ago
4 0
The chemical compound is Diborane<span> </span>
You might be interested in
Be sure to answer all parts. In the average adult male, the residual volume (RV) of the lungs, the volume of air remaining after
Alenkinab [10]

<u>Answer:</u>

<u>For a:</u> The number of moles of air present in the RV is 0.047 moles

<u>For b:</u> The number of molecules of gas is 2.83\times 10^{22}

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the number of moles, we use the equation given by ideal gas follows:

PV=nRT

where,

P = pressure of the air = 1.00 atm

V = Volume of the air = 1200 mL = 1.2 L    (Conversion factor:  1 L = 1000 mL)

T = Temperature of the air = 37^oC=[37+273]K=310K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of air = ?

Putting values in above equation, we get:

1.00atm\times 1.2L=n_{air}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 310K\\n_{air}=\frac{1.00\times 1.2}{0.0821\times 310}=0.047mol

Hence, the number of moles of air present in the RV is 0.047 moles

  • <u>For b:</u>

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules.

So, 0.047 moles of air will contain (0.047\times 6.022\times 10^{23})=2.83\times 10^{22} number of gas molecules.

Hence, the number of molecules of gas is 2.83\times 10^{22}

7 0
3 years ago
Which acide will have more strength<br>out of two acids of pH<br>value 2<br>and 5 why<br>​
gladu [14]

Ph 2 will ahve more strength due to the fact that its more acidic compared to pH 5.

the lower the number of a pH, the more it is heading towards being acidic, but the higher the number, the more it heads towards being an alkali. here is a ppt i made along time ago. hope it can help you . have a nice day

Download pptx
5 0
3 years ago
How many molecules is 7.22 mole H2O
Vinil7 [7]

Answer:

no H2O molecules are produced:)

Explanation:

6 0
3 years ago
Read 2 more answers
Rory answered that absolute zero is 0°K. Is this answer correct? Explain why or why not.
Ierofanga [76]

Answer:

Yes, this answer is correct.

Explanation:

Absolute zero is -273.15 degrees celsius

T= Tc+273.15

T is the kelvin temperature

Tc is the temperature in degrees celsius

substitute;

T= -273.15 + 273.15

T=0 K

:)

5 0
3 years ago
Which group on the periodic table already stable?
viktelen [127]
The noble gases AKA the column with full outermost valence shells. (Group 18)
7 0
3 years ago
Read 2 more answers
Other questions:
  • Which equation obeys the law of conservation of mass?
    14·2 answers
  • An electrolytic cell Group of answer choices consumes electrical current to drive a nonspontaneous chemical reaction. produces e
    10·1 answer
  • HURRY I WILL GRANT 100 PTS AND BRAINLIEST
    12·1 answer
  • There are two parts of photosynthesis--the light reactions and the dark reactions. What is the end product of the dark reactions
    15·2 answers
  • What is another name for a beta minus (β–) particle?
    15·1 answer
  • The combustion of a 0.4255 g sample of a compound containing carbon, hydrogen, oxygen and bromine produces 0.4961 g CO2 and 0.17
    13·1 answer
  • How do Earth's lithosphere,hydrosphere,and atmosphere compare?
    11·2 answers
  • What is Chronatography
    9·2 answers
  • How could we stop an asteroid that we know was going to hit Earth?<br><br><br> Pls help ASAP
    9·2 answers
  • Increase food supplies in an ecosystem decrease competition because the competing organsims would
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!