The answer is 607g. the working is shown above.
PLZ ANSWER WILL GIVE BRAINEST Based on the information in the table, which elements are most likely in the same periods of the p
eriodic table?
-Boron and carbon are likely together in one period because they have very close atomic numbers, while gallium and germanium are likely together in another period because they have very close atomic numbers.
-Aluminum, boron, and carbon are likely together in one period because they were first isolated in the first half of the 1800s, while gallium and germanium are likely together in another period because they were first isolated in the second half.
-Boron and carbon are likely together in one period because they each end in “-on,” while aluminum, gallium, and germanium are likely together in another period because they each end in “-ium.”
-Aluminum, boron, and gallium are likely together in one group because they have the same number of valence electrons, and carbon and germanium are likely together in another group because they have the same number of valence electrons.
-Boron and carbon are likely together in one period because they have very close atomic numbers, while gallium and germanium are likely together in another period because they have very close atomic numbers.
-Aluminum, boron, and carbon are likely together in one period because they were first isolated in the first half of the 1800s, while gallium and germanium are likely together in another period because they were first isolated in the second half.
-Boron and carbon are likely together in one period because they each end in “-on,” while aluminum, gallium, and germanium are likely together in another period because they each end in “-ium.”
-Aluminum, boron, and gallium are likely together in one group because they have the same number of valence electrons, and carbon and germanium are likely together in another group because they have the same number of valence electrons.
2 answers:
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Answer:
- [Ag⁺] = 1.3 × 10⁻⁵M
- s = 3.3 × 10⁻¹⁰ M
- Because the common ion effect.
Explanation:
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<u>1. Value of [Ag⁺] in a saturated solution of AgCl in distilled water.</u>
The value of [Ag⁺] in a saturated solution of AgCl in distilled water is calculated by the dissolution reaction:
- AgCl(s) ⇄ Ag⁺ (aq) + Cl⁻ (aq)
The ICE (initial, change, equilibrium) table is:
- AgCl(s) ⇄ Ag⁺ (aq) + Cl⁻ (aq)
I X 0 0
C -s +s +s
E X - s s s
Since s is very small, X - s is practically equal to X and is a constant, due to which the concentration of the solids do not appear in the Ksp equation.
Thus, the Ksp equation is:
- Ksp = [Ag⁺] [Cl⁻]
- Ksp = s × s
- Ksp = s²
By substitution:
- 1.8 × 10⁻¹⁰ = s²
- s = 1.34 × 10⁻⁵M
Rounding to two significant figures:
- [Ag⁺] = 1.3 × 10⁻⁵M ← answer
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<u>2. Molar solubility of AgCl(s) in seawater</u>
Since, the conentration of Cl⁻ in seawater is 0.54 M you must introduce this as the initial concentration in the ECE table.
The new ICE table will be:
- AgCl(s) ⇄ Ag⁺ (aq) + Cl⁻ (aq)
I X 0 0.54
C -s +s +s
E X - s s s + 0.54
The new equation for the Ksp equation will be:
- Ksp = [Ag⁺] [Cl⁻]
- Ksp = s × ( s + 0.54)
- Ksp = s² + 0.54s
By substitution:
- 1.8 × 10⁻¹⁰ = s² + 0.54s
- s² + 0.54s - 1.8 × 10⁻¹⁰ = 0
Now you must solve a quadratic equation.
Use the quadratic formula:
The positive and valid solution is s = 3.3×10⁻¹⁰ M ← answer
<u>3. Why is AgCl(s) less soluble in seawater than in distilled water.</u>
AgCl(s) is less soluble in seawater than in distilled water because there are some Cl⁻ ions is seawater which shift the equilibrium to the left.
This is known as the common ion effect.
By LeChatelier's principle, you know that an increase in the concentrations of one of the substances that participate in the equilibrium displaces the reaction to the direction that minimizes this efect.
In the case of solubility reactions, this is known as the common ion effect: when the solution contains one of the ions that is formed by the solid reactant, the reaction will proceed in less proportion, i.e. less reactant can be dissolved.
Answer:
The reaction is not at equilibrium and reaction must run in forward direction.
Explanation:
At the given interval, concentration of NO =
Concentration of =
Concentration of NOBr =
Reaction quotient, , for this reaction =
species inside third bracket represents concentrations at the given interval.
So,
So, the reaction is not at equilibrium.
As therefore reaction must run in forward direction to increase
and make it equal to
.