4.0 % in mass per volume :
4.0 g ---------- 100 mL
1.2 g ---------- ( volume )
Volume = 1.2 x 100 / 4.0
Volume = 120 / 4.0
= 30 mL
hope this helps!
Answer is: concentration of hydrogen iodide is 6 M.
Balanced chemical reaction: H₂(g) + I₂(g) ⇄ 2HI(g).
[H₂] = 0.04 M; equilibrium concentration of hydrogen.
[I₂] = 0.009 M; equilibrium concentration of iodine.
Keq = 1·10⁵.
Keq = [HI]² / [H₂]·[I₂].
[HI]² = [H₂]·[I₂]·Keq.
[HI]² = 0.04 M · 0.009 M · 1·10⁵.
[HI]² = 36 M².
[HI] = √36 M².
[HI] = 6 M.
Answer:
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Hi sorry
I don’t know
but maybe next time
Is that all? That doesn’t help us give the answers