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4 years ago

The frequency of sound wave determines what?

Chemistry

1 answer:

dangina [55]4 years ago

5 0

The frequency of sound wave determined pitch. Pitch is determined as how high or low a sound is.

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Since this reaction takes place in acidic solution, H2O(l) and H+(aq) will be involved in the reaction. Places for these species

maxonik [38]

Answer:

The balanced equation is given below:

SO4^2−(aq)+ Sn^2+(aq) + 4H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)

The coefficients of the reactants are: 1, 1, 4

The coefficients of the products are: 1, 1, 1

Explanation:

Step 1:

The equation for the reaction. This is given below:

SO4^2−(aq)+ Sn^2+(aq) + –––→ H2SO3(aq)+ Sn^4+(aq) + –––

Step 2:

Inclusion of H+ and H2O into the equation. This is illustrated below:

SO4^2−(aq)+ Sn^2+(aq) + H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)

Step 3:

Balancing the equation.

SO4^2−(aq)+ Sn^2+(aq) + H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)

The above equation can be balanced as follow:

There are total 4 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 4 in front of H^+ as shown below:

SO4^2−(aq)+ Sn^2+(aq) + 4H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)

Now the equation is balanced.

The coefficients of the reactants are: 1, 1, 4

The coefficients of the products are: 1, 1, 1

5 0

3 years ago

Mg(OH)2 is a sparingly soluble salt with a solubility product, Ksp, of 5.61×10−11. It is used to control the pH and provide nutr

Solnce55 [7]

Answer:

The ration of the molar solubility is 165068.49.

Explanation:

The solubility reaction of the magnesium hydroxide in the pure water is as follows.

$Mg(OH)_{2}\Leftrightarrow Mg^{2+}(aq)+2(OH)^{-}(aq)$

$[Mg^{2+}][OH^{-}]$

Initial 0 0

Equili +S +2S

Final S 2S

$K_{sp}=[Mg^{2+}][OH^{-}]$

$5.61\times 10^{-11}=(S)(2S)^{2}$

$S=(\frac{5.61\times 10^{-11}}{4})^{1/3}=2.41\times 10^{-4}M$

Solubility of $Mg(OH)_{2}$ in 0.180 M NaOH is a follows.

$Mg(OH)_{2}\Leftrightarrow Mg^{2+}(aq)+2(OH)^{-}(aq)$

$[Mg^{2+}][OH^{-}]$

Initial 0 0

Equili +S +2S

Final S 2S+0.180M

$K_{sp}=[Mg^{2+}][OH^{-}]$

$5.61\times 10^{-11}=(S)(2S+0.180)^{2}$

$S=1.46\times 10^{-9}M$

$Ratio\,of\,solubility=\frac{2.41\times 10^{-4}}{1.46\times 10^{-9}}=165068.49$

Therefore, The ration of the molar solubility is 165068.49.

4 0

3 years ago

Convert 7.89 x 10^8 molecules of water to liters.

NNADVOKAT [17]

Answer:

2.94 x 10⁻¹⁴L

Explanation:

To solve this problem, we have to assume that the condition of this water is at standard temperature and pressure, STP.

At STP;

1 mole of gas have a volume of 22.4L

So, let us find the number of moles of this water first;

6.02 x 10²³ molecules can be found in 1 mole of a substance

7.89 x 10⁸ molecules will contain $\frac{7.89 x 10^{8} }{6.02 x 10^{23} }$ = 1.31 x 10⁻¹⁵mole of water

So;

Volume of water = 22.4 x 1.31 x 10⁻¹⁵ = 2.94 x 10⁻¹⁴L

5 0

3 years ago

In Earth's water cycle, evaporation takes place as solid ice and snow are converted to water vapor. true or false?

valentinak56 [21]

This is true, vapor is just evaporated water. Like in machines, you have to fill it up with water so your machine can produce the water vapor. Hope this helps!!

4 0

3 years ago

Read 2 more answers

Three compounds containing potassium and oxygen are compared. Analysis shows that for each 1.00 g of O, the compounds have 1.22

kicyunya [14]

The law of proportion states that elements combine in whole number ratios. The gram readings for K are multiples of each other, both in grams and moles.
Let us compare the ratios:
2.44 grams/1.22 grams = 2
4.89 grams/2.44 grams = 2

Therefore, Potassium always combines with Oxygen in a ratio of 2 is to 1.

4 0

4 years ago