Answer:
Approximately .
Assumption: air resistance is negligible.
Explanation:
Make sure all the values are in standard units.
.
The bounce here is an inelastic collision between the ball and the surface. Some of the kinetic energy (KE) was lost. The exact value of energy loss would be equal to .
Before the bounce, all the kinetic energy of the ball would come from the drop from . That is:
.
After the bounce, the ball travels to a height of . All the potential energy gained in that process should come from the kinetic energy when the ball bounces back from the ground.
.
Hence, the size of energy loss due to the bounce would be equal to
.
Answer:
Pls ezplain your question more
Explanation:
Answer:
Explanation:
gauge pressure due to a liquid column of density d and height h is given by the following expression .
P = hdg
The pressure depends upon height of liquid column and not on the cross sectional area .
In first cylinder .
gauge pressure = .40 atm
hdg = .40 atm
cross sectional area of cylinder = π r²
The radius of second cylinder is twice of the first , cross sectional area will be 4 times .
The volume remains the same when the liquid is poured into second cylinder
volume = cross sectional area x height .
As cross sectional area of second cylinder is 4 times , height of liquid column in second cylinder = h / 4 .
gauge pressure in second cylinder = h / 4 x d x g = hdg / 4
.40 / 4 = .10 atm
gauge pressure in second cylinder = .10 atm.
North China in Asia. hope that helps