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MissTica
4 years ago
8

Find the lateral area of the square pyramid

Mathematics
1 answer:
fredd [130]4 years ago
5 0

Lateral Area, namely the area of its sides, namely excluding its base.

well, the pyramid is standing on one of its triangular faces, so we'll have to exclude that.

now, let's notice, is a square pyramid, so it has an 8x8 square, and it has triangular faces that have a <u>base of 8 and a height of 22</u>.

\bf \stackrel{\textit{square's area}}{(8\cdot 8)}~~+~~\stackrel{\textit{3 triangular faces' area}}{3\left[ \cfrac{1}{2}(8)(22) \right]}\implies 64+264\implies 328

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A study is performed in a large southern town to determine whether the average amount spent on food per four-person family in th
hoa [83]

Step-by-step explanation:

H0: u = 150

H1: u ≠ 150

Total sum = 15933.24

N = 100

Mean = 15933.24/100

= 159.3324

σ² = 25954.03 - (159.3324)²/100

σ² = 556.213

σ = √556.213

σ = 23.8162

Testing hypothesis

t = (bar x - u)/ σ/√n

= 159.3324-150/23.8162/√100

= 3.91

We will have a p value of 0.02

0.0002 < 0.01

We reject null hypothesis at 1% level of significance

C. Mean = 159.3324

Se= 2.3936

Df = 100-1 = 99

Critical value at 0.01 = +-2.626

T = x-u/s.e

= -2.626 =( x -150)/2.3936

When we cross multiply and solve this

X = 143.714 for the lower tail

2.626 = (x-159)/2.3936

= 156.286 for upper tail.

We therefore reject H0 at

Bar X <= 143.71

Bar X >= 156.286

At 10%

Critical t = 1.660

-1.660 = (x - 150)/2.3936

Solving this ,

X =146.02 at the lower tail

1.660 = (x-150)/2.3936

X = 153.97

We reject H0 at

X<= 146.03

X>=153.97

4 0
3 years ago
Mateo wants to make a toy sailboat. He has two pieces of wood to choose from.
jeka94

Answer:

wut is it

Step-by-step explanation:

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Write two point-slope equations for the line passing through the points (6, 5) and (3, 1)
Lady_Fox [76]

Answer:

Point-slope equations:

y - 5 = 4/3 (x - 6)

or

y - 1 = 4/3 (x - 3)

Step-by-step explanation:

Given two coordinate points (6, 5) and (3, 1)

Slope = (5 - 1)/(6 - 3) = 4/3

Point-slope equations:

y - 5 = 4/3 (x - 6)

or

y - 1 = 4/3 (x - 3)

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3 years ago
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If you reflect the coordinates (1,4) across the y-axis what would be the new<br> coordinates? *
Sati [7]

Answer:

-1,4

Step-by-step explanation:

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Calculate 42kg of 105kg as a percentage
yulyashka [42]
\frac{42\,\mathrm{kg}}{105\,\mathrm{kg}} = \frac{2\cdot21}{5\cdot 21} = \frac{2}{5} = \frac{4}{10}=40\%
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