i am there but i can't talk now
cause my mom is calling
but sorry!!
In this question, you are given the NaOH volume but asked for concentration.
Don't forget that for every 1 mol of NaOH there will be 1 mol OH- ion, but for every 1 mol of H2SO4 there will be 2 mol of H- ion.
To neutralize you need the same amount of OH- and H+, so the equation should be:
OH-= H+
<span>35.50cm3 * x*1= 25cm3* 0.2mol/dm3 *2
</span>x= 10/35.5 mol/dm3= 0.2816/dm3
Answer:
nitrogen
Explanation:
The stoichiometry of the reaction says that 
and 
react 3:1 to form 2 moles of 
, so, if you have 3,5 moles of H, which is equal to 1,75 moles of , and 5 moles of N, which are equal to 2,5 moles of 
. only
=0.583 moles of , will react, leaving <em>1.917 moles of </em> <em>unreacted</em>, and forming 0.583*2=1.166 moles of
It has more density when it sinks because the water pushes away thats why people float they are less dense
No, the dilution does not change the number of moles dissolved
Explanation:
We can see that,
The molarity of the solution was 0.50 M
The volume of the solution is 10 ml.
No of moles of the solute was= volume * concentration
= 10 X 10^-3* 0.50
= 5*10^-3 moles
When the solution is diluted from 10 ml to 100ml, the molarity or concentration changes but number of moles remains constant.
The molarity of 100 ml solution will be
c=n/V
= 5*10^-3*/100*10^-3
= 0.05
when the solution is diluted to 100ml from 10 ml molarity changes from 0.5M TO 0.05 M
