Answer:
The correct answer is Option
B. A homogeneous mixture
Explanation: Mixture is solution which is made of two or more than two substances which are combined only physically not chemically. There are two types of mixture i. e. Homogeneous mixture and heterogeneous mixture. Homogeneous mixture is a mixture in which the substances which are combined are uniform in appearance and heterogeneous mixture is a mixture in which substances are suspended in the solution and easily differentiated.
![\text{Ammonia has been studied as an alternative "clean" fuel for internal combustion}](https://tex.z-dn.net/?f=%5Ctext%7BAmmonia%20has%20been%20studied%20as%20an%20alternative%20%22clean%22%20fuel%20for%20internal%20combustion%7D)
![\text{engines, since its reaction with oxygen produces only nitrogen and water vapor,}](https://tex.z-dn.net/?f=%5Ctext%7Bengines%2C%20since%20its%20reaction%20with%20oxygen%20produces%20only%20nitrogen%20and%20water%20vapor%2C%7D)
![\text{and in the liquid form it is easily transported. An industrial chemist studying this}](https://tex.z-dn.net/?f=%5Ctext%7Band%20in%20the%20liquid%20form%20it%20is%20easily%20transported.%20An%20industrial%20chemist%20studying%20this%7D)
![\text{reaction fills a} \ \mathbf{100 \ L }\ \text{tank with} \ \mathbf{8.6 \ mol} \ \text{of ammonia gas and} \ \mathbf{28 \ mol} \ \ \text{of oxygen gas, }](https://tex.z-dn.net/?f=%5Ctext%7Breaction%20fills%20a%7D%20%5C%20%5Cmathbf%7B100%20%5C%20%20L%20%7D%5C%20%5Ctext%7Btank%20with%7D%20%5C%20%5Cmathbf%7B8.6%20%5C%20mol%7D%20%5C%20%5Ctext%7Bof%20ammonia%20gas%20and%7D%20%5C%20%5Cmathbf%7B28%20%5C%20mol%7D%20%5C%20%5C%20%20%5Ctext%7Bof%20oxygen%20gas%2C%20%7D)
![\text{to be} \ \mathbf{2.6\ mol} \ .\ \text{Calculate the concentration equilibrium constant for the combustion of}](https://tex.z-dn.net/?f=%5Ctext%7Bto%20be%7D%20%5C%20%20%5Cmathbf%7B2.6%5C%20%20mol%7D%20%5C%20.%5C%20%5Ctext%7BCalculate%20the%20concentration%20equilibrium%20constant%20for%20the%20combustion%20of%7D)
![\text{ammonia at the final temperature of the mixture. Round your answer to 2 significant digits.}](https://tex.z-dn.net/?f=%5Ctext%7Bammonia%20at%20the%20final%20temperature%20of%20the%20mixture.%20Round%20your%20answer%20to%20%202%20significant%20digits.%7D)
Answer:
Explanation:
From the correct question above:
The reaction can be represented as:
![\mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }](https://tex.z-dn.net/?f=%5Cmathbf%7B4%20NH_3_%7B%28g%29%7D%2B%203O_%7B2%28g%29%7D%20%5Ciff%202N_%7B2%28g%29%7D%2B%206H_2O_%7B%28g%29%7D%20%7D)
From the above reaction; the ICE table can be represented as:
![\mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }](https://tex.z-dn.net/?f=%5Cmathbf%7B4%20NH_3_%7B%28g%29%7D%2B%203O_%7B2%28g%29%7D%20%5Ciff%202N_%7B2%28g%29%7D%2B%206H_2O_%7B%28g%29%7D%20%7D)
I (mol/L) 0.086 0.28 0 0
C -4x -3x +2x +6x
E 0.086 - 4x 0.28 - 3x +2x +6x
At equilibrium;
The water vapor = ![\dfrac{2.6 \ mol}{100 \ L} = 6x](https://tex.z-dn.net/?f=%5Cdfrac%7B2.6%20%5C%20mol%7D%7B100%20%5C%20L%7D%20%3D%206x)
![x = \dfrac{2.6}{100} \times \dfrac{1}{6}](https://tex.z-dn.net/?f=x%20%3D%20%5Cdfrac%7B2.6%7D%7B100%7D%20%5Ctimes%20%5Cdfrac%7B1%7D%7B6%7D)
![x = 0.00433](https://tex.z-dn.net/?f=x%20%3D%200.00433)
![\text{equilibrium constant} ({k_c}) = \dfrac{ [N_2]^2 [H_2O]^6 }{ [[NH_3]^4] [O_2]^3 }](https://tex.z-dn.net/?f=%5Ctext%7Bequilibrium%20constant%7D%20%20%28%7Bk_c%7D%29%20%3D%20%20%5Cdfrac%7B%20%5BN_2%5D%5E2%20%5BH_2O%5D%5E6%20%7D%7B%20%5B%5BNH_3%5D%5E4%5D%20%5BO_2%5D%5E3%20%7D)
![\implies \dfrac{(2x)^2 (6x)^6}{(0.086-4x)^4\times (0.28-3x)^3} \\ \\](https://tex.z-dn.net/?f=%5Cimplies%20%5Cdfrac%7B%282x%29%5E2%20%286x%29%5E6%7D%7B%280.086-4x%29%5E4%5Ctimes%20%280.28-3x%29%5E3%7D%20%5C%5C%20%5C%5C)
Replacing the value of x, we have:
![K_c = \dfrac{4 \times 46,656 \times x^8}{(0.086-4x)^4\times (0.28 -3x)^3} \\ \\ K_c = \dfrac{4 \times 46656 \times (0.00433)^8}{(0.06868)^4(0.26701)^3} \\ \\ K_c = \mathbf{5.4446 \times 10^{-8}}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cdfrac%7B4%20%5Ctimes%2046%2C656%20%5Ctimes%20x%5E8%7D%7B%280.086-4x%29%5E4%5Ctimes%20%280.28%20-3x%29%5E3%7D%20%5C%5C%20%5C%5C%20K_c%20%3D%20%5Cdfrac%7B4%20%5Ctimes%2046656%20%5Ctimes%20%280.00433%29%5E8%7D%7B%280.06868%29%5E4%280.26701%29%5E3%7D%20%5C%5C%20%5C%5C%20K_c%20%3D%20%5Cmathbf%7B5.4446%20%5Ctimes%2010%5E%7B-8%7D%7D)
![K_c = \mathbf{5.5 \times 10^{-8} \ to \ 2 \ significant \ figures}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cmathbf%7B5.5%20%5Ctimes%2010%5E%7B-8%7D%20%5C%20to%20%20%5C%202%20%5C%20significant%20%5C%20figures%7D)
In order for plants to go through photosynthesis, they must use <span>B. visible light.</span>
Answer:
Isotopes are variants of an element, where the number of neutrons is different but its number of protons stay the same.
Explanation:
If the number of protons had changed then it would just be a different element.
Electron number changing simply adds charge to the atom, and doesn't change it or anything.
PLS GIVE BRAINLIEST
1 mole = 6.022×10^23 atoms. 1 water molecule = 2 Hydrogen atoms + 1 oxygen atom. So, 1 mole H2O = 1.2044×10^24 hydrogen atoms. Therefore 2 mole H2O will have 2.4088×10^24 hydrogen atoms.