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julia-pushkina [17]
3 years ago
10

Why do elements that make positive ions occur on the left side of the periodic table while those that make negative ions occur o

n the right?
Chemistry
1 answer:
Lynna [10]3 years ago
8 0

Answer:

Elements in the same group have the same number of valence electrons.

Explanation: Science.

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Fast food and juice boxes are example of which of these?
ser-zykov [4K]

Answer:

habitat destruction I think

Explanation:

4 0
2 years ago
Is my answer right?
Ahat [919]
Yes the answer is 1s22s22p63s23p64s23d5
7 0
3 years ago
What happens when carbon dioxide is passed through lime water for a long time? write with equation​
Vlada [557]

Answer:

when CO2 gas is passed through lime water it turns milky due to the formation of calcium carbonate which formula is CaCO3.

Ca(OH)2+ CO2------ CaCO3

when excess of carbon dioxide is passed through calcium carbonate calcium hydrogen carbonate is formed and solution become colourless.

CaCO3+CO2------ Ca(HCO3)

5 0
3 years ago
An atom gets over all positive charge by ____ _______
Rasek [7]
<h2>Answer:</h2>

Nucleus.

<h2>Explanation:</h2>
  • In an atom the nucleus has an overall positive charge as it contains the protons.
  • Every atom has no overall charge (neutral). While atoms do contain charged particles, they have the same number of positive protons as negative electrons( for example a sodium atom has 11 electrons which are of negative charge and 11 protons which are of positive charge).
  • These opposite charges cancel each other out making the atom neutral.

Result: Nucleus is the overall positive charge of an atom.

4 0
3 years ago
The reaction is first order in cyclopropane and has a measured rate constant of k=3.36×10−5 s−1 at 720 k. if the initial cyclopr
sergey [27]

Answer:

0.0277 M.

Explanation:

The integral rate law of a first order reaction:

<em>Kt = ln ([A₀]/[A]),</em>

where, k is the rate constant of the reaction <em>(k = 3.36 × 10⁻⁵ s⁻¹)</em>,

t is the time of the reaction <em>(t = 235.0 min = 14100 s)</em>,

[A₀] is the initial concentration of cyclopropane <em>([A₀] = 0.0445 M)</em>

<em>∵ Kt = ln ([A₀]/[A]),</em>

∴ (3.36 × 10⁻⁵ s⁻¹)(14100 s) = ln (0.0445 M)/[A]

Taking the exponential of both sides:

1.6 = (0.0445 M)/[A]

<em>∴ [A] = (0.0445 M)/1.6 = 0.0277 M.</em>

<em />

6 0
3 years ago
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