The answer is: " 208 g " .
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Explanation:
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The formula/ equation for density is:
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D = m / V ; That is, "mass divided by volume" ;
Density is expressed as:
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"mass per unit volume"; in which the "mass" is expressed in units of "g" ("grams") ; and the "unit volume" is expressed in units of:
"cm³ " or "mL";
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{Note the exact equivalent: 1 cm³ = 1 mL }.
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→ The formula is: " D = m / V " ;
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in which:
"D" refers to the "density" (see above), which is: "8.9 g/cm³ " (given);
"m" refers to the "mass" , in units of "g" (grams), which is unknown; and we want to find this value;
"V" refers to the "volume", in units of "cm³ " ;
which is: "23.4 cm³ " (given);
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We want to find the mass, "m" ; so we take the original equation/formula for the density:
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D = m / V ;
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And we rearrange; to isolate "m" (mass) on ONE side of the equation; and then we plug in our known/given values;
to solve for "m" (mass); in units of "g" (grams) ;
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Multiply each side of the equation by "V" ;
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V * { D = m / V } ; to get:
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V * D = m ; ↔ m = V * D ;
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Now, we plug in the given values for "V" (volume) and "D" (density) ; to solve for the mass, "m" ;
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m = V * D ;
m = (23.4 cm³) * (8.9 g / 1 cm³) = (23.4 * 8.9) g = 208.26 g ;
→ Round to "208 g" (3 significant figures);
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The answer is: " 208 g " .
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3.85 pounds is the answer
There’s 10mm in a cm: 22mm
Answer:
108 km
Explanation:
The conversion factor between meters and feet is
1 m = 3.28 ft
So the second altitude, written in feet, can be rewritten in meters as
![h_2 = 1.55 \cdot 10^5 ft \cdot \frac{1}{3.28 ft/m}=4.7\cdot 10^4 m](https://tex.z-dn.net/?f=h_2%20%3D%201.55%20%5Ccdot%2010%5E5%20ft%20%5Ccdot%20%5Cfrac%7B1%7D%7B3.28%20ft%2Fm%7D%3D4.7%5Ccdot%2010%5E4%20m)
or in kilometers,
![h_2 = 47 km](https://tex.z-dn.net/?f=h_2%20%3D%2047%20km)
the first altitude in kilometers is
![h_1 = 155 km](https://tex.z-dn.net/?f=h_1%20%3D%20155%20km)
so the difference between the two altitudes is
![\Delta h = 155 km - 47 km = 108 km](https://tex.z-dn.net/?f=%5CDelta%20h%20%3D%20155%20km%20-%2047%20km%20%3D%20108%20km)