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3 years ago

I need help with my physics homework agh! Please help it's due tomorrow.

Physics

1 answer:

storchak [24]3 years ago

4 0

Rubbing both pieces cause each piece to have a negative charge.

When two parts have the same they repel each other, so holding one piece up tot he end of the other piece would push it away.

Because one piece is held in the middle by a string, it would rotate the piece in a circle.

If they held the piece to the other end of the one held by a string it would start to rotate in the opposite direction.

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Which automobile is faster a chevrolet or a ford? Also explain pls

antiseptic1488 [7]

Answer:

depends on what type of car it is

Explanation:

6 0

2 years ago

Read 2 more answers

Which of the following statements explains how total time spent in the air is affected as a projectile's angle of launch is incr

charle [14.2K]

Answer:

Therefore letter C is the correct answer.

Explanation:

In a projectile motion the total time in the air can be calculated using the following equation:

We analyze the y-component motion.

$v_{fy}=v_{iy}-gt$

When the final velocity (v(f)) is equal to zero we calculate the upward time and multiplying it by 2 we find the total time in the air. So we will have:

$t_{tot}=2\frac{v_{iy}}{g}$

$t_{tot}=2\frac{v_{i}sin(\theta)}{g}$

We can see that the total time is directly proportional to the angle, then when θ increase t increase.

Therefore letter C is the correct answer.

I hope it helps you!

3 0

2 years ago

In which of these situations would there be the least kinetic energy?

Alexandra [31]

C. a truck rolling down hill

7 0

2 years ago

What is the value of the composite constant (Gme,/r2e) to be multiplied by the mass of the object mo, in equation below:

Sedbober [7]

To solve this problem we will apply the definitions given in Newtonian theory about the Force of gravity, and the Force caused by weight. Both will be defined below, and in equal equilibrium condition to clear the variable concerning acceleration due to gravity. Finally, with the values provided in the statement, it will be replaced.

The equation for the gravitational force between the Earth and the object on the surface of the Earth is

$F_g = \frac{Gm_em_o}{r^2_e}$

Where,

G = Universal gravitational constant

$m_e$ = Mass of Earth

$r_e$ = Distance between object and center of earth

$m_o$ = Mass of Object

The equation for the gravitational pulling force on the object due to gravitational acceleration is

$F_g = m_o g$

Equation the two expression we have

$m_o g = \frac{Gm_em_o}{r_e^2}$

$g = \frac{Gm_e}{r_e^2}$

This the acceleration due to gravity which is composite constant.

Replacing with our values we have then

$g = \frac{(6.67*10^{-11}N\cdot m^2/kg^2)(5.98*10^{24}kg)}{6378km(\frac{10^3m}{1km})^2}$

$g = 9.8m/s^2$

The value of composite constant is $9.8m/s^2$ . Here, the composite constant is nothing but the acceleration due to gravity which is constant always.

8 0

3 years ago

A box of books is in the floor. The following picture shows a push and a pull acting in the box.

nataly862011 [7]

Net force = 50 + 50 = 100 M
Since two forces act towards the same direction , total force should be their sum amd towards the same direction as the two forces

8 0

3 years ago

I need help with my physics homework agh! Please help it's due tomorrow. ​

I need help with my physics homework agh! Please help it's due tomorrow.