Answer: -
IE 1 for X = 801
Here X is told to be in the third period.
So n = 3 for X.
For 1st ionization energy the expression is
IE1 = 13.6 x Z ^2 / n^2
Where Z =atomic number.
Thus Z =( n^2 x IE 1 / 13.6)^(1/2)
Z = ( 3^2 x 801 / 13.6 )^ (1/2)
= 23
Number of electrons = Z = 23
Nearest noble gas = Argon
Argon atomic number = 18
Number of extra electrons = 23 – 18 = 5
a) Electronic Configuration= [Ar] 3d34s2
We know that more the value of atomic radii, lower the force of attraction on the electrons by the nucleus and thus lower the first ionization energy.
So more the first ionization energy, less is the atomic radius.
X has more IE1 than Y.
b) So the atomic radius of X is lesser than that of Y.
c) After the first ionization, the atom is no longer electrically neutral. There is an extra proton in the atom.
Due to this the remaining electrons are more strongly pulled inside than before ionization. Hence after ionization, the radii of Y decreases.
The species that represents an ion is B³+ (option A).
<h3>What is an ion?</h3>
An ion is an atom or group of atoms bearing an electrical charge, such as the sodium and chlorine atoms in a salt solution.
Simply put, an ion is said to be an electrically charged atom. This refers to the difference in the number of protons and electrons in the atom of an element.
According to this question, the species with an electrical charge is B³+, hence, it represents an ion.
Learn more about ion at: brainly.com/question/14982375
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Answer:
6 molecules of H2O are the maximum number.
Explanation:
From the drawing it can be seen that there are 6 H2 molecules and 3 O2 molecules reacting, which can be represented by the following chemical equation
6 H2 + 3 O2 ⇒ H2O
This equation is not balanced, so we proceed to balance it, being as follows:
6 H2 + 3 O2 ⇒ 6H2O
With which it can be determined that a maximum of 6 H2O molecules can be formed.
C4H10 is an alkane (propane to be precise)
The relative formula mass of a molecule of propane is
(12x4) + (1x10) = 58
because a carbon atom has an atomic weight of 12 and a hydrogen atom has an atomic weight of 1.
Answer:
Mass = 8 g
Explanation:
Given data:
Mass of MgO formed = 20 g
Mass of oxygen needed = ?
Solution:
Chemical equation:
2Mg + O₂ → 2MgO
Number of moles of MgO:
Number of moles = mass/molar mass
Number of moles = 20 g/ 40 g/mol
Number of moles = 0.5 mol
Now we will compare the moles of MgO and O₂ from balance chemical equation:
MgO : O₂
2 : 1
0.5 : 1/2×0.5 = 0.25 mol
Mass of oxygen required:
Mass = number of moles × molar mass
Molar mass of O₂ is 32 g/mol
Mass = 0.25 mol × 32 g/mol
Mass = 8 g
