How much energy is required to raise 10 grams of water by 10 degrees Celsius? (in Joules)
2 answers:
<u>Answer:</u> The amount of heat required by water is 418.6 J
<u>Explanation:</u>
To calculate the heat absorbed by water, we use the equation:
where,
q = heat absorbed
m = mass of water = 10 g
c = heat capacity of water = 4.186 J/g°C
= change in temperature = 10°C
Putting values in above equation, we get:
Hence, the amount of heat required by water is 418.6 J
You might be interested in
C. Aluminum (Al) oxidized, zinc (Zn) reduced
<h3>Further explanation</h3>Given
Metals that undergo oxidation and reduction
Required
A galvanic cell
Solution
The condition for voltaic cells is that they can react spontaneously, indicated by a positive cell potential.
or:
E ° cell = E ° reduction-E ° oxidation
For the reaction to occur spontaneously (so that it E cell is positive), the E° anode must be less than the E°cathode
If we look at the voltaic series:
<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au </em>
The standard potential value(E°) from left to right in the voltaic series will be greater, so that the metal undergoing an oxidation reaction (acting as an anode) must be located to the left of the reduced metal (as a cathode)
<em />
From the available answer choices, oxidized Al (anode) and reduced Zn (cathode) are voltaic/galvanic cells.