How much energy is required to raise 10 grams of water by 10 degrees Celsius? (in Joules)
2 answers:
<u>Answer:</u> The amount of heat required by water is 418.6 J
<u>Explanation:</u>
To calculate the heat absorbed by water, we use the equation:
where,
q = heat absorbed
m = mass of water = 10 g
c = heat capacity of water = 4.186 J/g°C
= change in temperature = 10°C
Putting values in above equation, we get:
Hence, the amount of heat required by water is 418.6 J
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The answer for the following question is mentioned below.
<u><em>Therefore no of moles present in the gas are 1.12 moles</em></u>
Explanation:
Given:
Pressure of gas (P) = 1.2 atm
Volume of a gas (V) = 50.0 liters
Temperature (T) =650 K
To calculate:
no of moles present in the gas (n)
We know;
According to the ideal gas equation;
We know;
<u>P × V = n × R × T </u>
where,
P represents pressure of the gas
V represents volume of the gas
n represents no of the moles of a gas
R represents the universal gas constant
where the value of R is 0.0821 L atm mole^{-1} K^-1
T represents the temperature of the gas
As we have to calculate the no of moles of the gas;
n =
n = \frac{1.2*50.0}{0.0821*650}
n = \frac{60}{53.365}
n = 1.12 moles
<u><em>Therefore no of moles present in the gas are 1.12 moles</em></u>
Answer:
<h2>The answer is 7.14 g/mL</h2>Explanation:
The density of a substance can be found by using the formula
From the question
mass of metal = 25 g
volume = final volume of water - initial volume of water
volume = 28.5 - 25 = 3.5 mL
It's density is
We have the final answer as
<h3>7.14 g/mL</h3>Hope this helps you