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Lisa [10]
3 years ago
9

How many Mg atoms are found in 1.00 mole of MgO?

Chemistry
1 answer:
ipn [44]3 years ago
7 0

Answer:

From the equation above we get 1 amu = 1g/NA or 1 amu = 1.66054x10^-24 g. Thus, a mole of magnesium atoms has a mass of NA x 24.305 amu x (1.66054x10^-24 g/amu) = 24.305 g. A mole of magnesium atoms has a mass of 24.305 g.

Explanation:

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Por que el petroleo es un no recurso renovable
mote1985 [20]

Answer:

Por ejemplo, el petróleo o el carbón son ejemplos de recursos no renovables porque, aunque se forman mediante un proceso natural, este necesita demasiado tiempo. ... Esos combustibles fósiles provienen de materia orgánica, pero tardan cientos de miles de años en producirse.

3 0
3 years ago
A(n)____ is a ripened ovary
V125BC [204]
A(n) fruit is a ripened ovary
7 0
3 years ago
What is the molecular formula of a compound given the molar mass of the compound is 62.18 g/mol and the empirical formula is c2h
Mariulka [41]
To get the molecular formula we use the individual atomic masses of the atoms making the molecule. Hence, to get the factor by which the empirical formula is multiplied, we divide molar mass by the total of the mass of the atoms making the empirical formula.
(C2H7) the mass of one carbon atoms is 12 so two atoms add up to 24. The mass of one hydrogen atom is 1 a.m.u thus 7 atoms give a total of 7 a.m.u. The sum of the two types of atoms is 24+7= 31
Molar mass=62.18
62.18/31=2.0
Hence, (C2H7) 2=C4H14
5 0
3 years ago
Hydrogen sulfide decomposes according to the following reaction, for which Kc=9.30E-8 at 700 degrees Celsius. 2 H2S(g) --> 2
Svetlanka [38]

Answer: The equilibrium concentration of H_2(g) at 700 degrees Celsius is 0.0012 M

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c


Moles of  H_2S = 0.29 mole

Volume of solution = 3.0 L

Initial concentration of H_2S = \frac{0.29mol}{3.0L}=0.097M

The given balanced equilibrium reaction is,

                    2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

         Initial conc.         0.097 M           0M          0M

At eqm. conc.    (0.097-2x) M            (2x) M   (x) M

The expression for K_c is written as:

K_c=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}

K_c=\frac{(2x)^2\times x}{(0.097-2x)^2}

9.30\times 10^{-8}=\frac{(2x)^2\times x}{(0.097-2x)^2}

x=0.00060

Equilibrium concentration of [H_2]= 2x= 2\times 0.00060=0.0012M

6 0
3 years ago
From this figure, why are there only two possible values for the spin quantum number?
V125BC [204]

Answer:

bcoz there is  only two magnetic file orienation is possible

Explanation:

7 0
3 years ago
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