H:C:::N: (hydrogen cyanide). All atoms have formal charge of 0.
A gas made up of atoms escapes through a pinhole 0.225times as fast as gas. Write the chemical formula of the gas.
Answer:
Explanation:
To solve this problem, we must apply Graham's law of diffusion. This law states that "the rate of diffusion or effusion of a gas is inversely proportional to the square root of its molecular mass at constant temperature and pressure".
Mathematically;
r₁ is the rate of diffusion of gas 1
r₂ is the rate of diffusion of gas 2
m₁ is the molar mass of gas 1
m₂ is the molar mass of gas 2
let gas 2 be the given H₂;
molar mass of H₂ = 2 x 1 = 2gmol⁻¹
rate of diffusion is 0.225;
i .e r1/r2 = 0.225
0.225 = √2 / √ m₁
0.225 = 1.414 / √ m₁
√ m₁ = 6.3
m₁ = 6.3² = 39.5g/mol
The gas is likely Argon since argon has similar molecular mass
Answer is: 1,92 mol/L·s.
Chemical reaction: 2D(g) + 3E(g) + F(g) → <span>2G(g) + H(g).
</span>H is increasing at 0,64 mol/L·<span>s.
From chemical reaction n(H) : n(E) = 1 : 3.
0,64 mol : n(E) = 1 : 3.
n(E) = 1,92 mol.
</span>E is decreasing at 1,92 mol/L·s.
To find this, we will use this formula:
Molar mass of element
------------------------------------ x 100
Molar mass of compound
So, first lets calculate the mass of the compound as a whole. We use the atomic masses on the periodic table to determine this.
Ca: 40.078 g/mol
N2 (there is two nitrogens): 28.014 g/mol
O6 (there are six nitrogens: 3 times 2): 95.994 g/mol
When we add all of those numbers up together, we get 164.086. That is the molar mass for the whole compound. However, we are trying to figure out what percent of the compound oxygen makes up. From the molar mass, we know that 95.994 of the 164.086 is oxygen. Lets plug those numbers into our equation!
95.994
-----------
164.086
When we divide those two numbers, we get .585. When we multiply that by 100, we get 58.5.
So, the percent compostition of oxygen in Ca(NO3)2, or, calcium nitrate, is 58.5%.
A covalent bond is your answer
