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2 years ago

What are other materials found in the earth's crust

Chemistry

1 answer:

Kitty [74]2 years ago

7 0

Answer:

From mud and clay to diamonds and coal, Earth's crust is composed of igneous, metamorphic, and sedimentary rocks. The most abundant rocks in the crust are igneous, which are formed by the cooling of magma. Earth's crust is rich in igneous rocks such as granite and basalt.

Explanation:

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A true statement about mass is that:

Orlov [11]

Answer:

(c.) as the force of Earth's gravity on an object increases, the object's mass increases

Explanation:

Based on newton's law of gravitation "every particle of matter in the universe attracts every other particle with a force that is directly proportional to the product of the masses of the particles and inversely proportional to the square of the distance between them".

It is mathematically expressed as:

F = $\frac{Gm_{1} m_{2} }{r^{2} }$

F is the gravitational force on either particle

m₁ and m₂ are the masses

r is the distance between particles

G is the universal gravitation constant.

From this expression, we see that the force of earth's gravity is directly proportional to mass.

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2 years ago

The scientific method is the way scientists solve problems. Scientists begin to solve a problem by making _____.

swat32

Answer:

Explanation: observations

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2 years ago

The reaction below is at dynamic equilibrium. mc004-1.jpg Which statement is true for the equilibrium system? The concentration

enyata [817]

When a system is in dynamic equilibrium, the forward reaction rate and the backward reaction rate are equal or occurs at the same rate. Therefore, the third option above is the most accurate one. Hope this answers the question. Have a nice day.

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3 years ago

Read 2 more answers

What is the theoretical yield of aluminum that can be produced by the reaction of 60.0 g of aluminum oxide with 30.0 g of carbon

Varvara68 [4.7K]

Answer: 31.8 g

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} Al_2O_3=\frac{60.0g}{102g/mol}=0.59moles$

$\text{Moles of} C=\frac{30.0g}{12g/mol}=2.5moles$

$Al_2O_3+3C\rightarrow 2Al+3CO$

According to stoichiometry :

1 mole of $Al_2O_3$ require 3 moles of $C$

Thus 0.59 moles of $Al_2O_3$ will require= $\frac{3}{1}\times 0.59=1.77moles$ of $C$

Thus $Al_2O_3$ is the limiting reagent as it limits the formation of product and $C$ is the excess reagent as it is present in more amount than required.

As 1 mole of $Al_2O_3$ give = 2 moles of $Al$