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strojnjashka [21]
4 years ago
9

Is material that has a density of 0.2g/ml good for building a bridge or for making couch cushions

Chemistry
2 answers:
lisov135 [29]4 years ago
8 0
D = 0.2 g / ml = 0.2 g / cm³
For example, density of steel is 7.85 g / cm³.
Density of pure water is 1.0 g/cm³. An object which has a density < 1.0 g/cm³ will float in water.
Answer: Material that has a density of 0.2 g/ml ( 0.2 g/cm³ ) is good for making couch cushions. 
Ber [7]4 years ago
5 0

The density of an object refers to its mass per unit volume. The density of an object is determined by its mass, its size and arrangement of its atom. The mathematical formula for density is given by: Density = Mass / volume. The density of a substance is part of the determinant of what the substance can be used for. The density of an object depends on how tightly its molecules are packed. A substance with loosely packed molecules will have low density while a substance with tightly packed particles will have high density.

A material with 0.2g/ml density have low density, thus, such an object will not be suitable for holding large weight. Therefore it will be suitable for making couch cushion.

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1) Minimum mass of methane required to heat 45.0 g of water by 21.0°C is 0.0788 g.

2) Minimum mass of methane required to heat 50.0 g of water by 26.0°C is 0.108 g.

Explanation:

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g) ,\Delta H_{rxn} =-802.3 kJ

1) Minimum mass of  methane required to raise the temperature of water by 21.0°C.

Mass of water = m = 45.0 g

Specific heat capacity of water = c = 4.18 J/g°C

Change in temperature of water = ΔT = 21.0°C.

Heat required to raise the temperature of water by 21.0°C = Q

Q=mc\Delta T= 45.0 g\times 4.18 J/g^oC\times 21.0^oC

Q = 3,950.1 J = 3.9501 kJ

According to reaction 1 mole of methane on combustion gives 802.3 kJ of heat.

Then 3.950.1 kJ of heat will be given by:

=\frac{3.950.1 kJ}{802.3 kJ}=0.004923 mol

Mass of 0.004923 moles of methane :

0.004923 mol × 16 g/mol=0.0788 g

Minimum mass of methane required to heat 45.0 g of water by 21.0°C is 0.0788 g.

2) Minimum mass of  methane required to raise the temperature of water by 26.0°C.

Mass of water = m = 50.0 g

Specific heat capacity of water = c = 4.18 J/g°C

Change in temperature of water = ΔT = 26.0°C.

Heat required to raise the temperature of water by 21.0°C = Q

Q=mc\Delta T= 50.0 g\times 4.18 J/g^oC\times 26.0^oC

Q = 5,434 J= 5.434 kJ

According to reaction 1 mole of methane on combustion gives 802.3 kJ of heat.

Then 5.434 kJ of heat will be given by:

=\frac{5.434 kJ}{802.3 kJ}=0.006773 mol

Mass of 0.006773 moles of methane :

0.006773 mol × 16 g/mol= 0.108 g

Minimum mass of methane required to heat 50.0 g of water by 26.0°C is 0.108 g.

6 0
4 years ago
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