Answer:
There will be produced:
2.97 moles HMnO4
4.45 moles Pb(NO3)2
2.97 moles H2O
Explanation:
Step 1: Data given
Manganese(II) oxide = MnO2
lead(IV) oxide = PbO2
nitric acid = HNO3
Moles of HNO3 = 8.90 moles
Step 2: The balanced equation
2MnO2 + 3PbO2 + 6HNO3 → 2HMnO4 + 3Pb(NO3)2 + 2H2O
Step 3: Calculate moles of reactants and products
For 2 moles MnO2 we need 3 moles PbO2 and 6 moles HNO3 to produce 2 moles HMnO4, 3 moles Pb(NO3)2 and 2 moles of water
For 8.90 moles of HNO3, there will react:
8.90 / 3 = 2.97 moles MnO2
8.90 / 2 = 4.45 moles PbO2
There will be produced:
8.90/3 = 2.97 moles HMnO4
8.90/2 = 4.45 moles Pb(NO3)2
8.90 / 3 = 2.97 moles H2O
Answer: THREE<span> different isomers can be derived from ethylene if two hydrogen atoms are replaced by a fl uorine atom and a chlorine atom.
Explanation: When two Hydrogen atoms in ethylene (
C</span>
₂H₄) are replaced with Fluorine and Chlorine atom then the new molecular formula is
C₂H₂FCl.
Compounds having same Molecular formula but different structural formula are called as Isomers.
First Isomer of C₂H₂FCl is
1-chloro-1-fluoroethene, in which F and Cl at geminal position (attached to same Carbon atom).
Other two Isomers are
Geometrical Isomers of
1-chloro-2-fluoroethene, in which F and Cl at different carbon atom and having different position is space. The one in which both F and Cl at opposite side forms
(<em>
trans</em>
)-1-chloro-2-fluoroethene and the one in which both are in same side is called as
(<em>
cis</em>
)-1-chloro-2-fluoroethene.
Answer:
(a) 17,178 mg/m3
(b) 11,625 mg/m3
Explanation:
The concentration of CO in mg/m3 can be calculated as

For standard conditions (1 atm and 25°C), P/RT is 0.0409.
Concentration of 1.5% percent by volume of CO is equivalent to 1.5*10,000 ppm= 15,000 ppm CO.
The molecular weigth of CO is 28 g/mol.
(1) For 25°C and 1 atm conditions

(b) For 200°C and 1.1 atm,

Then the concentration in mg/m3 is

Metals usually melt when forming iron