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statuscvo [17]
3 years ago
10

Plzzzz helppppp meeee

Chemistry
1 answer:
Sedbober [7]3 years ago
8 0

Answer:

If the question is how much mass would two atoms of Ag have you take the atomic mass and multiply by 2 = 215.5

Explanation:

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EastWind [94]
These could all go either way, hardness and other special properties are what I'm guessing would be the most accurate in determining the kind of material.
luster, cleavage, streak, and color can all be affected by other factors. but I guess cleavage would also be accurate. so I guess hardness special properties and cleavage would be the most reliable.
4 0
2 years ago
A reaction occurs in a calorimeter, resulting in the starting and final temperatures shown below. What can you say about the rea
ELEN [110]

"The reaction is exothermic and ΔH is negative" can be understood about the reaction and the enthalpy change (ΔH) during the reaction.

<u>Option: D</u>

<u>Explanation:</u>

When the reaction is positive, the process becomes endothermic, i.e. heat appears to be consumed by the system because the reaction products are more enthalpic than the reactants. When the reaction is negative, on the other hand, the process is exothermic, which is the total decrease in enthalpy is caused by heat production. Here the initial temperature is 21.0 C but increase in final temperature to 38.8 C, because if some processes require heat, others must give off heat when they take place.

4 0
3 years ago
Which of the following occupies a volume?<br><br> solids<br> liquids<br> gases<br> all of the above
nataly862011 [7]
Solids occupy a volume
7 0
3 years ago
Read 2 more answers
What is the name of this molecule?
Sunny_sXe [5.5K]

Answer:

D. cis-2-pentene (looks like a frying pan)

Explanation:

pentane looks lihe the letter M

2-methylpentane looks like YV

2-pentyne looks like an upside down L

8 0
2 years ago
Calculate the percent ionization of propionic acid (C2H5COOH) in solutions of each of the following concentrations (Ka is given
tekilochka [14]

Answer:

a) = 0.704%

b) = 1.30%

c) = 2.60%

Explanation:

Given that:

K_a= 1.34*10^{-5

For Part A; where Concentration of A = 0.270 M

Percentage Ionization(∝)  \alpha = \sqrt{\frac{K_a}{C} }

\alpha = \sqrt{\frac{1.34*10^{-5}}{0.270} }

\alpha = \sqrt{4.9629*10^{-5}}

\alpha = 7.044*10^{-3

percentage% (∝) = 7.044*10^{-3}*100

= 0.704%

For Part B; where Concentration of B = 7.84*10^{-2 M

\alpha = \sqrt{\frac{1.34*10^{-5}}{7.84*10^{-2}} }

\alpha = \sqrt{1.709*10^{-4} }

\alpha = 0.0130\\

percentage% (∝) = 0.0130 × 100%

= 1.30%

For Part C; where Concentration of C= 1.92*10^{-2} M

\alpha = \sqrt{\frac{1.34*10^{-5}}{1.97*10^{-2}} }

\alpha = \sqrt{6.802*10^{-4}}

\alpha =0.02608

percentage% (∝) = 0.02608  × 100%

= 2.60%

7 0
3 years ago
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