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Elis [28]
3 years ago
13

A single alkyl bromide reactant theoretically yields either of the given products, depending on the reaction conditions. Draw th

e structure of the alkyl bromide compound.

Chemistry
2 answers:
Ierofanga [76]3 years ago
8 0

Answer:

H_{3}C--H_{3}C--CH_{3}--Br--CH_{3}

Explanation:

The steps involved in predicting the structure of the alkyl bromide compound are outlined below.

1) An examination of the product shows that the product could only be formed by a substitution reaction.

2) The structure of the alkyl bromide compound can be then predicted by replacing the methoxide group in the product after the substitution of bromine atom. This is because the methoxide ion acts as a strong nucleophile.

Therefore, by consideration the reaction mechanisms of reactions 1 and 2, it can be predicted that the structure of the alkyl bromide compound is H_{3}C--H_{3}C--CH_{3}--Br--CH_{3}. A pictorial diagram of the alkyl bromide compound is also attached.

Sergeu [11.5K]3 years ago
5 0

Answer:

Yields an ether either with one step reaction or may undergo a bimolecular reaction

Explanation:

Here the substitution reactions of alkyl halides: explores two mechanisms.

Step 1:

 The reaction takes place in a single step- direction, bond-breaking and bond-forming occur simultaneously this is a dissociative and produces carbonation. SN1 Reaction

Or

Step 2: bimolecular reaction and it is stereoselective. SN2

Note: As a rule, nucleophilic substitutions occur at sp3-hybridized carbons, and not where the leaving group is attached to an sp2-hybridized carbon.

Bonds on sp2-hybridized carbons are inherently shorter and stronger than bonds on sp3 - hybridized carbons, meaning that it is harder to break the C-X (Halide) bond in these substrates.

Where as SN2 reactions of this type are unlikely also because the (hypothetical) electrophilic carbon is protected from nucleophilic attack by electron density in the p bond.

SN1 reactions are highly unlikely, because the resulting carbocation intermediate, which would be sp-hybridized, would be very unstable .

So this above births the expression theoretical yield. Here is a question and the reactions.

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What depends on the type of acid some acid you have to use plastic or aluminum to store
5 0
3 years ago
A chemical engineer determines the mass percent of iron in an ore sample by converting the Fe to Fe²⁺ in acid and then titrating
neonofarm [45]

The mass percent of iron in the ore is 31.6%

<h3>Steps</h3>

8H⁺(aq) + 5Fe²⁺(aq) + MnO⁻₄(aq) → 5Fe³⁺(aq) + Mn²⁺(aq) + 4H₂O(l)

V(MnO4^-)=39,32 mL

c(MnO4^-)=0,0319M

n(MnO4^-)=c*V=1,254308 mmol

n(Fe^{2+})=5*n(MnO4^-)=6,27 mmol

Equation

Fe+2H->Fe^+2 + H2

n(Fe)=n(Fe^{2+} )=6,27 mmol

m(Fe)=n*Ar=350,27mg=0,35027g

mass percent(Fe in ore)=m(Fe)/m(ore)*100

=31,61 percent

The mass percent of iron in the ore is 31.6%

<h3>What is the equation for the balance formula?</h3>

An equation for a chemical reaction is said to be balanced if both the reactants and the products have the same number of atoms and total charge for each component of the reaction. In other words, both sides of the reaction have an equal balance of mass and charge.

<h3>An illustration of a balanced equation</h3>

For instance, consider about the reaction: O2 (g) + 2Mg(s) = 2MgO (g) Two magnesium and two oxygen atoms are present in this reaction on both the reactant and product sides.

learn more about balanced equation here

brainly.com/question/26694427

#SPJ4

8 0
1 year ago
A sample of 42 mL of carbon dioxide gas was placed in a piston in order to maintain a constant 101 kPa of pressure.
Lilit [14]

Answer:

The answer to your question is 33.4 ml

Explanation:

Data

volume 1 = V1 = 42 ml

temperature 1 = T1 = 20°C

temperature 2 = T2 = -60°C

Volume 2 = V2 = x

Process

1.- Convert celsius to kelvin

T1 = 20 + 273 = 293°K

T2 = -60 + 273 = 233°K

2.- Use the Charles' law to solve this problem

               \frac{V1}{T1} = \frac{V2}{T2}

Solve for V2

                V2 = \frac{V1T2}{T1}

3.- Substitution

               V2 = \frac{(42)(233)}{293}

4.- Simplification

                V2 = \frac{9786}{293}

5.- Result

                V2 = 33.4ml

3 0
3 years ago
What is the pH of a solution prepared by dissolving<br>0.8 g NaOH in water to make 200 mL solution?​
Ad libitum [116K]

Answer:

pH>7

Explanation:

bases tend to increase the pH of a solution. since water has the pH of 7 and NaOH has pHof 14, the overall pH of solution will increase.

hope it's helpful.

3 0
4 years ago
Read 2 more answers
Thank uuuu so much!!!!!
kow [346]

Answer:

A. 0.83

Explanation:

Hopefully this helps!

7 0
3 years ago
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