Question

Raw sewage is raised vertically by 5.49m in the amountof

Answer 1

Answer:

          P = 1235.7646 W

Explanation:

Given data:

height of raised sewage = 5.49 m

rate of sewage =1.89*10^6 lt/day

density of sewage = 1.050 kg/m^3

power is written as

$P = \frac{work}{time}$

work  = m g h

$m - mass = ( \rho V)$

  h -height

mass lifted per day $= ( 1.89*10^6)(1.050)$

                              = 1984500 kg

time = 24 hours* 3600 seconds per hour

power$P = \frac{( 1984500)(9.8)( 5.49)}{(24)(3600)}$

          P = 1235.7646 W