1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ruslelena [56]
4 years ago
5

You go to the hardware store to buy a new 50 ft garden hose. You find you can choose between hoses of ½ inch and 5/8 inch inner

diameter. Compared the rate at which water flows through the two types of hoses (i.e. the ratio of rates).
Physics
1 answer:
omeli [17]4 years ago
3 0

To solve this problem it is necessary to consider two concepts. The first of these is the flow rate that can be defined as the volumetric quantity that a channel travels in a given time. The flow rate can also be calculated from the Area and speed, that is,

Q = V*A

Where,

A= Cross-sectional Area

V = Velocity

The second concept related to the calculation of this problem is continuity, which is defined as the proportion that exists between the input channel and the output channel. It is understood as well as the geometric section of entry and exit, defined as,

Q_1 = Q_2

V_1A_1=V_2A_2

Our values are given as,

A_1=\frac{1}{2}^2*\pi=0.785 in^2

A_2=\frac{5}{8}^2*\pi=1.227 in^2

Re-arrange the equation to find the first ratio of rates we have:

\frac{V_1}{V_2}=\frac{A_2}{A_1}

\frac{V_1}{V_2}=\frac{1.227}{0.785}

\frac{V_1}{V_2}=1.56

The second ratio of rates is

\frac{V2}{V1}=\frac{A_1}{A2}

\frac{V2}{V1}=\frac{0.785}{1.227}

\frac{V2}{V1}=0.640

You might be interested in
Why does Mercury have so little gas in its atmosphere? Choose one or more: A. Its escape velocity is low. B. It has a high tempe
Slav-nsk [51]

Answer:

Option A, B, C and D

Explanation:

First to all, we need to remember something. Mercury is the first planet to our solar system, therefore, it's the closest planet to the sun. Because of this, temperatures of that planet are way too high.

Mercury has a very thin atmosphere so it barely exists. It also has a low gravity and receives large gusts of solar winds from the Sun, that's why it has high temperature, and therefore, it's escape velocity is very low too.

Of course, it's one of the smallest planets in our solar system, so,the atmosphere of Mercury is unstable and constantly shifting. As the atmosphere’s materials are being made, they are also being taken away at the uppermost layers due to solar winds. The composition of the atmosphere can also change as you move across the planet.

3 0
3 years ago
One end of a metal rod is in contact with a thermal reservoir at 699. K, and the other end is in contact with a thermal reservoi
bulgar [2K]

Answer:

a)ΔS₁ = - 9.9 J/K

ΔS₂ = 69 J/K

b)The entropy change for the rod = 0 J/K

c)ΔS = 59.1 J/K

Explanation:

Given that

T₁ = 699 K

T₂= 101 K

Q= 6970 J

Change in entropy given as

\Delta S=\dfrac{Q}{T}

For 699 K:

\Delta S_1=\dfrac{Q}{T}

\Delta S_1=-\dfrac{6970}{699}

ΔS₁ = - 9.9 J/K  ( Negative because heat is leaving from the system)

For 101 K;

\Delta S_2=\dfrac{Q}{T}

\Delta S_2=\dfrac{6970}{101}

ΔS₂ = 69 J/K

The entropy change for the rod = 0 J/K

Entropy  change for the system

ΔS = ΔS₂  + ΔS₁

ΔS = 69 -9.9 J/K

ΔS = 59.1 J/K

8 0
3 years ago
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse
NISA [10]

Answer:

The time interval is t  =  5.48 *10^{-3} \ s

Explanation:

From the question we are told that

   The length of the string is  l  =  3.00 \ m

    The  mass of the string is m  =  5.00 \ g  =  5.0 *10^{-3}\ kg

     The  tension on the string is  T  =  500 \ N

   

The  velocity of the pulse is mathematically represented as

      v  = \sqrt{ \frac{T}{\mu } }

Where \mu is the linear density which is mathematically evaluated as

       \mu  =  \frac{m}{l}

substituting values

     \mu  =  \frac{5.0 *10^{-3}}{3}

     \mu  = 1.67 *10^{-3} \  kg /m

Thus  

     v = \sqrt{\frac{500}{1.67 *10^{-3}} }

    v = 547.7 m/s

The time taken is evaluated as

    t  =  \frac{d}{v}

substituting values

      t  =  \frac{3}{547.7}

      t  =  5.48 *10^{-3} \ s

5 0
4 years ago
20 PTS BRAINLIEST If Thomson's model of the atom was correct, what would Rutherford have seen in his experiments?
Sati [7]
The correct option is A.
J.J Thompson proposed the plum model of atomic structure. The model states that the atom is a sphere of positively charged matter in which electrons are embedded.
Rutherford designed an experiment to verify the truth of this model. He set up a beam of alpha particles which are to be passed a thin gold foil. If the JJ model of atomic structure is correct, all of the alpha particles suppose to pass through the foil, but some of the alpha particles bounced back while those that passed through the foil emerged at different angles.
5 0
3 years ago
Read 2 more answers
An automobile accelerates from zero to 30 m/s in 6.0 s. The wheels have a diameter of 0.40 m. What is the average angular accele
leva [86]

To solve this problem we will use the concepts related to angular motion equations. Therefore we will have that the angular acceleration will be equivalent to the change in the angular velocity per unit of time.

Later we will use the relationship between linear velocity, radius and angular velocity to find said angular velocity and use it in the mathematical expression of angular acceleration.

The average angular acceleration

\alpha = \frac{\omega_f - \omega_0}{t}

Here

\alpha = Angular acceleration

\omega_{f,i} = Initial and final angular velocity

There is not initial angular velocity,then

\alpha = \frac{\omega_f}{t}

We know that the relation between the tangential velocity with the angular velocity is given by,

v = r\omega

Here,

r = Radius

\omega = Angular velocity,

Rearranging to find the angular velocity

\omega = \frac{v}{r}}

\omega = \frac{30}{0.20} \rightarrow Remember that the radius is half te diameter.

Now replacing this expression at the first equation we have,

\alpha = \frac{30}{0.20*6}

\alpha = 25 rad /s^2

Therefore teh average angular acceleration of each wheel is 25rad/s^2

3 0
3 years ago
Other questions:
  • How much force is required to keep the object moving with the same speed and on the same direction
    11·1 answer
  • A car travels with an average speed of 55 miles/hr. What is this speed in
    13·1 answer
  • Jennifer, who has a mass of 50.0 kg, is riding at 35.0 m/s in her red sports car when she must suddenly slam on the brakes to av
    6·1 answer
  • Calculate the wavelength and frequency at which the intensity of the radiation is a maximum for a blackbody at 298 K. You will n
    8·1 answer
  • g a 240 V<0 source source supplies a balance, three-phase load in a delta configuration. The line current is 3 A<45. What
    9·1 answer
  • Sort the characteristics of solids, liquids, and gases into the correct columns.
    9·2 answers
  • Why are recessive traits not seen even though they are present in the alleles?​
    13·1 answer
  • . The p.d. at the terminals of a battery is 25V when no load is connected and 24V when a load taking 10A is connected. Determine
    5·1 answer
  • The resultant of two vectors is of magnitude 3 units and 4 units is 1 units, what is the value of their dot product? ​
    11·1 answer
  • What type of foods do bodyguards eat give 5 examples
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!