1. the positioning of the sun
2. equinox
3. summer solstice
Answer:
a) h = 593.50 m
b) h₁₁ = 103 m
c) vf = 107.91 m/s
Explanation:
a)
We will use second equation of motion to find the height:
where,
h = height = ?
vi = initial speed = 0 m/s
t = time taken = 11 s
g = 9.81 /s²
Therefore,
<u>h = 593.50 m</u>
b)
For the distance travelled in last second, we first need to find velocity at 10th second by using first equation of motion:
where,
vf = final velocity at tenth second = v₁₀ = ?
t = 10 s
vi = 0 m/s
Therefore,
Now, we use the 2nd equation of motion between 10 and 11 seconds to find the height covered during last second:
where,
h = height covered during last second = h₁₁ = ?
vi = v₁₀ = 98.1 m/s
t = 1 s
Therefore,
<u>h₁₁ = 103 m</u>
c)
Now, we use first equation of motion for complete motion:
where,
vf = final velocity at tenth second = ?
t = 11 s
vi = 0 m/s
Therefore,
<u>vf = 107.91 m/s</u>
A. To solve for part A, we use the formula of Young’s
double slit equation:
x = λ L m / d<span>
</span>Where,
x = distance between adjacent dark lines or fringes =
12.5 cm = 0.125 m
λ = wavelength of light = 600 × 10^-9 m
L = distance from the two sources of light to
the screen = 1.2 m
m = number of fringes = 10 (tenth) – 1 (first)
= 9
d = separation of slits = unknown
Rearranging the equation in terms of d and
plugging in the values:
d = λ L m / x
d = (600 × 10^-9 m) (1.2 m) (9) / 0.125 m
d = 5.184 × 10^-5 m
d = 51.84 μm
B. The formula for path difference is:
path difference = (2 m + 1) (λ / 2)<span>
path difference = (2 * 9 + 1) (</span>600 × 10^-9 m / 2)
<span>path
difference = 5.7 × 10-6 m</span>
<span>path difference = 5.7 μm</span>
Answer:
Explanation:
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
The mass of the wagon is 12 kilograms and the acceleration is 3 meters per square second.
Substitute the values into the formula.
Multiply.
- 1 kilogram meter per square second ( 1 kg*m/s²) is equal to 1 Newton (N)
- Our answer of 36 kg*m/s² is equal to 36 N
The force required for the 12 kilogram wagon to accelerate at 3 meters per square second is <u>36 Newtons.</u>
The root quadratic equation of is
What is the formula used to calculate the quadratic equation?
To solve the quadratic equation use the formula of
Find the quadratic equation by using the formula ?
On comparing with
We get ,
By using the formula,
For a quadratic equation of the form the solutions are
Apply rule,
Apply exponent rule,
if n is even
Multiply the numbers :
Add the number