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aev [14]
2 years ago
14

when a candle burns both physical and chemical changes take place at identify these changes give another example of a familiar p

rocess in which both the chemical and physical changes takes place. ​
Chemistry
1 answer:
sp2606 [1]2 years ago
8 0

Answer:

So, the melting of wax and vapourisation of melted wax are physical changes. Chemical Changes : The wax near flame burns and gives new substances like carbon dioxide, carbon soot, water vapour, heat and light. LPG is another example of a familiar process in which both the chemical and physical changes take place.

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Which is a physical change?
kotykmax [81]

Answer: Strawberries liquefied in a blender

Explanation:

3 0
3 years ago
A gas has a volume of 50.0 cm3 at a temperature of -73°c. what volume would the gas occupy at a temperature of -123°c if the pre
vaieri [72.5K]

Boyle’s Law illustrates the inverse relationship of volume and pressure. It follows the formula  p1V1 = P2V2 , where P1V1 denotes initial pressure and volume  and P2V2 denotes values of pressure and  volume.

Now, let us work out for what is asked above.
a. if the pressure is doubled
50.0 p = V x 2p 
V = 50.0 p / 2p

= 50.0 /2

= 25.0 m^3 
b. if the pressure is cut in half
50.0 p = V x p/2 
100 p = V x p 
V = 100 m^3 
c. if the pressure is tripled
50.0 p = V x 3p 
V = 50.0 p / 3p

= 50.0 /3

=16.7 m^3 

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7 0
2 years ago
Why is it so important to use more than just fossil fuels for our energy sources?​
blsea [12.9K]

Answer:

Fossil Fuels have the ability to pollute and trash our ecosystems. Its better for us to use clean and renewable energy too.

Explanation:

8 0
2 years ago
The specific heat of copper is 0.40 joules/ g °c. How much heat is needed in joules to change the temperature of a 55 gram subst
Snezhnost [94]

Answer : The amount of heat needed is, 1188 J

Explanation :

Formula used :

q=m\times c\times (T_2-T_1)

where,

q = heat needed = ?

m = mass of copper = 55 g

c = specific heat capacity of copper = 0.40J/g^oC

T_1 = initial temperature = 20.0^oC

T_2 = final temperature = 74.0^oC

Now put all the given values in the above formula, we get:

q=55g\times 0.40J/g^oC\times (74.0-20.0)^oC

q=1188J

Thus, the amount of heat needed is, 1188 J

3 0
3 years ago
Groundwater in an area flows at a speed of 4km/h. How long would it take the water to flow 10 km t it’s springs
joja [24]
You want to divide 10 by 4 to get the number of hours it will take for the water to get to the springs, which is 2.5, so it would take the water 2.5 hours to revel to it’s spring
6 0
3 years ago
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