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d1i1m1o1n [39]
3 years ago
15

Electron configuration of calcium

Chemistry
1 answer:
Eva8 [605]3 years ago
5 0
1s2 2s2 2p6 3s2 3p6 4s2 is the electron configuration for Calcium
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What element breaks down into yttrium-90?
atroni [7]

The correct answer is Strontium-90.

Strontium-90 breaks down into yttrium-90.

Strontium-90  is a radioactive isotope of strontium. It undergoes β− decay into yttrium-90. A decay energy of 0.546 MeV is also released.

⁹⁰₃₈Sr   -> ⁰₋₁e + ⁹⁰₃₉Yr

Beta particle has the charge and mass of an electron. Upon the release of a beta particle, the mass number of Sr remains unchanged but the atomic number of Sr increases by 1. As a result both Sr and Yt have mass number 90, however, Sr and Yt have atomic numbers 38 and 39 respectively.

8 0
4 years ago
When an object's speed and direction are known, so is its _____. A. mass B. velocity C. momentum D. acceleration
dexar [7]

D. acceleration

Explanation:

When an object's speed and direction are known, its acceleration can also be determined.

Acceleration is defined as the change in velocity of a body in motion with time.

Most times, velocity and speed can be changed if the direction a body is traveling is known.

            Acceleration  = \frac{Change in velocity }{time}

The S.I unit of acceleration is always expressed as m/s²

Learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

3 0
3 years ago
Read 2 more answers
In the following reaction, how many liters of oxygen will react with 124.5 liters of propane (C3H8), at STP?
nexus9112 [7]

In the following reaction,76.616 litre of oxygen will react

8 0
3 years ago
Determine the [ OH − ] , pH, and pOH of a solution with a [ H + ] of 8.2 × 10 − 10 M at 25 °C. [ OH − ] = 1.22 ×10 −5 M pH = 9.0
nika2105 [10]

Answer:

See explanation below

Explanation:

At the beggining of the  exercise, you already giving the solution for the 1st two problems, so I just going to answer the remaining question which are:

<em>"Determine the [ H + ] , [ OH − ] , and pOH of a solution with a pH of 7.20 at 25 °C. [ H + ] = M [ OH − ] = M pOH = 6.8 Determine the [ H + ] , [ OH − ] , and pH of a solution with a pOH of 6.43 at 25 °C."</em>

Now, to get every data in the problem, we need to write the expressions for every part, which are the following:

pH = -log[H⁺]   (1)

pH = 14 - pOH  (2)

[H⁺] = 10^(-pH)  (3)

[H⁺] = Kw / [OH⁻]   (4)

pOH = -log[OH⁻]  (5)

pOH = 14 - pH  (6)

[OH⁻] = 10^(-pOH)   (7)

[OH⁻] = Kw / [H⁺]  (8)

Now, according to the given data, we will use any of these eight expressions.

a) "<u><em>Determine the [ H + ] , [ OH − ] , and pOH of a solution with a pH of 7.20"</em></u>

We have pH, so in this case, we will use expression (3), (6) and (8):

[H⁺] = 10^(-7.20)

[H⁺] = 6.31x10⁻⁹ M

pOH = 14 - 7.2

pOH = 6.8

[OH⁻] = 1x10⁻¹⁴ / 6.31x10⁻⁹

[OH⁻] = 1.58x10⁻⁴ M

b) <u>"</u><u><em>The [ H + ] , [ OH − ] , and pH of a solution with a pOH of 6.43 "</em></u>

In this case, we can use expressions (2), (4) and (7). Using those expressions we have:

pH = 14 - 6.43

pH = 7.57

[H⁺] = 10^(-7.57)

[H⁺] = 2.69x10⁻⁸ M

[OH⁻] = 1x10⁻¹⁴ / 2.69x10⁻⁸

[OH⁻] = 3.72x10⁻⁷ M

4 0
4 years ago
The currents in our experiment are between 0 and 20 nanoAmperes. How many electrons per second are passing an ammeter if it read
stira [4]

The number of electrons per second passing an ammeter if it reads 10 nA is 6.24 × 10⁹ electrons per second

Since our current reads 10 nA and we require the number of electrons per second passing through the ammeter, 10 nA = 1 × 10⁻⁹ C/s.

Since there are 1.602 × 10⁻¹⁹ C/electron, the number of electrons per second, n = current/electron charge

= 1 × 10⁻⁹ C/s ÷ 1.602 × 10⁻¹⁹ C/electron

= 1/1.602 × 10¹⁰ electrons  

= 0.62422 × 10¹⁰ electrons per second

= 6.2422 × 10⁹ electrons per second

≅ 6.24 × 10⁹ electrons per second

So, the number of electrons per second passing an ammeter if it reads 10 nA is 6.24 × 10⁹ electrons per second

Learn more about electrons passing per second here:

brainly.com/question/14959684

5 0
3 years ago
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