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netineya [11]
3 years ago
13

I WILL MARK BRAINLY-EST Do you think the way we perceive food in our culture supports the guidelines in MyPlate? Explain your

Chemistry
1 answer:
Advocard [28]3 years ago
4 0
Yes, some cultures eat healthier due to restrictions on some foods they won’t eat due to their culture. So eating healthier because of that endorses the guidelines on my plate since they push us to eat healthier. One prime example is Japanese culture they believe in a balanced meal and balanced presentation.
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Most Bic lighters hold 5.0ml of liquified butane (density = 0.60 g/ml). Calculate the minimum size container you would need to "
Hatshy [7]

Answer:

Volume of container = 0.0012 m³ or 1.2 L or 1200 ml

Explanation:

Volume of butane = 5.0 ml

density = 0.60 g/ml

Room temperature (T) = 293.15 K

Normal pressure (P) = 1 atm = 101,325 pa

Ideal gas constant (R) = 8.3145 J/mole.K)

volume of container V = ?

Solution

To find out the volume of container we use ideal gas equation

PV = nRT

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

First we find out number of moles

<em>As Mass = density × volume</em>

mass of butane = 0.60 g/ml ×5.0 ml

mass of butane = 3 g

now find out number of moles (n)

n = mass / molar mass

n = 3 g / 58.12 g/mol

n = 0.05 mol

Now put all values in ideal gas equation

<em>PV = nRt</em>

<em>V = nRT/P</em>

V = (0.05 mol × 8.3145 J/mol.K × 293.15 K) ÷ 101,325 pa

V = 121.87 ÷ 101,325 pa

V = 0.0012 m³ OR 1.2 L OR 1200 ml

8 0
3 years ago
Nitrogen dioxide gas is dark brown in color and remains in equilibrium with dinitrogen tetroxide gas, which is colorless.
sukhopar [10]

Answer:

This reaction is exothermic because the system shifted to the left on heating.

Explanation:

2NO₂ (g) ⇌ N₂O₄(g)

Reactant => NO₂ (dark brown in color)

Product => N₂O₄ (colorless)

From the question given above, we were told that when the reaction at equilibrium was moved from room temperature to a higher temperature, the mixture turned dark brown in color.

This simply means that the reaction does not like heat. Hence the reaction is exothermic reaction.

Also, we can see that when the temperature was increased, the reaction turned dark brown in color indicating that the increase in the temperature favors the backward reaction (i.e the equilibrium shift to the left) as NO₂ which is the reactant is dark brown in color. This again indicates that the reaction is exothermic because an increase in the temperature of an exothermic reaction will shift the equilibrium position to the left.

Therefore, we can conclude that:

The reaction is exothermic because the system shifted to the left on heating.

8 0
3 years ago
A 36-gram sample of water has an initial temperature of 22°c. After the sample absorbs 1200 joules of heat energy, the final tem
professor190 [17]

Answer:

≈29.94 [°C].

Explanation:

all the details are in the attachment, the answer is underlined with orange colour.

7 0
2 years ago
The energy of colored light increases in the order red, yellow, green, blue, violet.List the metallic elements used in the flame
Vinil7 [7]

Answer:

Explanation:

Flame test:

The metals ions can be detected through the flame test. Different ions gives different colors when heated on flame. Tom perform the flame test following steps should follow:

1. Dip a wire loop in the solution of compound which is going to be tested.

2. After dipping put the loop of wire on bunsen burner flame.

3. Observe the color of flame.

4. Record the flame color produce by compound

Color produce by metals:

Red = Lithium, zirconium, strontium, mercury, Rubidium (red violet)

Orange-red = calcium

Yellow = sodium, iron (brownish yellow)

Green = green

Blue = cesium. arsenic, copper, tantalum, indium, lead

Violet = potassium (lilac)

3 0
4 years ago
The equilibrium constant for the reaction
FinnZ [79.3K]

Answer: The concentrations of Cl_2 at equilibrium is 0.023 M

Explanation:

Moles of  Cl_2 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{10g}{71g/mol}=0.14mol

Volume of solution = 1 L

Initial concentration of Cl_2 = \frac{0.14mol}{1L}=0.14M

The given balanced equilibrium reaction is,

                            COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)

Initial conc.           0.14 M           0 M       0M    

At eqm. conc.     (0.14-x) M        (x) M        (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}

Now put all the given values in this expression, we get :

4.63\times 10^{-3}=\frac{x)^2}{(0.14-x)}

By solving the term 'x', we get :

x = 0.023 M

Thus, the concentrations of Cl_2 at equilibrium is 0.023 M

7 0
3 years ago
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