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Delvig [45]
3 years ago
5

Because of this difference in entropy change, the net entropy change of the entire system is ________ during a real isothermal e

xpansion. Complete the sentence above.
Chemistry
1 answer:
Arada [10]3 years ago
8 0

Answer:

The net entropy change of the entire system is increasing during a real isothermal expansion.

Explanation:

The net entropy of a system is always zero for reversible process, and it is positive for irreversible  process. It is also important to notice that the net entropy is the change of total entropy, that means.

\Delta S_{Total} = \Delta S_{System} +\Delta S_{surroundings}

In a reversible isothermal process the total entropy change is 0, where the increase of entropy of the system has the same magnitude as the decrease of the entropy of the surroundings.

But in a real isothermal process the magnitude of the entropy lost by the surroundings is less than the magnitude of entropy gained by the system, thus we have irreversible process so the net entropy is always positive.

In case of a gas for example where we have isothermal expansion, the work done is by the gas, causing a heat loss by the surroundings. It is that temperature difference that will make the entropy lost by the surroundings less than the magnitude of entropy gained by the gas.

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Why do we need to use moles when we try to determine amounts of reactants and products in a reaction?.
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\huge\fbox{Answer ☘}

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What two structures would provide a positive identification of a plant cell under a microscope? a)cell wall, mitochondria b)plas
olga55 [171]

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The following molecular equation represents the reaction that occurs when aqueous solutions of silver(I) nitrate and calcium chl
dsp73

Answer:

Ag+(aq) + Cl-(aq) —> AgCl(s)

Explanation:

2AgNO3(aq) + CaCl2(aq) —>2AgCl(s) + Ca(NO3)2(aq)

The balanced net ionic equation for the reaction above can be obtained as follow:

AgNO3(aq) and CaCl2(aq) will dissociate in solution as follow:

AgNO3(aq) —> Ag+(aq) + NO3-(aq)

CaCl2(aq) —> Ca2+(aq) + 2Cl-(aq)

AgNO3(aq) + CaCl2(aq) –>

2Ag+(aq) + 2NO3-(aq) + Ca2+(aq) + 2Cl-(aq) —> 2AgCl(s) + Ca2+(aq) + 2NO3-(aq)

Cancel out the spectator ions i.e Ca2+(aq) and 2NO3- to obtain the net ionic equation.

2Ag+(aq) + 2Cl-(aq) —> 2AgCl(s)

Divide through by 2

Ag+(aq) + Cl-(aq) —> AgCl(s)

The, the net ionic equation is

Ag+(aq) + Cl-(aq) —> AgCl(s)

4 0
4 years ago
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