Answer:
(a) Iron is being oxidized.
(d) Sulfur is being reduced.
Explanation:
Let's consider the following redox reaction.
8 Fe(s) + S₈(s) → 8 FeS(s)
Iron is being oxidized according to the following oxidation half-reaction:
Fe(s) → Fe²⁺(s) + 2 e⁻
Sulfur is being reduced according to the following reduction half-reaction:
S₈(s) + 16 e⁻ → 8 S²⁻(s)
Answer:
Your cation is Pb2+
Explanation:
This is the explanation by chemical reactions
HCl (l) ----> H+(aq) + Cl-(aq)
Pb2+(aq) + 2Cl-(aq) ---> PbCl2 (s) ↓
H2SO4 (l) ----> 2H+ (aq) + SO4-2(aq)
Pb2+(aq) + SO4-2(aq) ---> PbSO4 (s) ↓
NaOH (l) ---> Na+(aq) + OH-(aq)
Pb2+(aq) + 2OH-(aq) ---> Pb(OH)2 (s) ↓
If the reaction takes place in a strong alkaline medium, lead hydroxide dissolves in excess of base
Answer:
Percent yield = 94.62%
Explanation:
Given data:
Actual yield of BeBr₂ = 1.23 mol
Theoretical yield of BeBr₂ = 220 g
Percent yield = ?
Solution:
Theoretical yield in moles:
Number of moles = mass/molar mass
Number of moles = 220 g/168.82 g/mol
Number of moles = 1.30 mol
Percent yield:
Percent tiled = actual yield / theoretical yield × 100
by putting values,
Percent yield = 1.23 mol / 1.30 mol × 100
Percent yield = 0.9462 × 100
Percent yield = 94.62%
Answer:
B. using efficient light bulbs
Answer:
b- swap the uses for iron oxide and calcium carbonate.
Explanation:
just took the test. good luck!